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svet-max [94.6K]
3 years ago
8

5 mile how many feet

Mathematics
2 answers:
Andreas93 [3]3 years ago
8 0
A mile is 5280 feet so you do 5 times 5280 to get 26400.
belka [17]3 years ago
7 0
5 miles = ? feet 

1 mile = 5280 feet 

5 x 5280 = 26400

ANSWER = 26400
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The scatter plot below represents the amount of dog food a brand recommends
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positive linear association

Step-by-step explanation:

the slope is positive so the linear association is also positive and linear mean generaly in a line not on a curve like a nonlinear assciation.

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2 years ago
What is the answer to this
arlik [135]

S\frac{O}{H} C\frac{A}{H} T\frac{O}{A} or Sin\frac{Opposite}{Hypotenuse}Cos\frac{Adjacent}{Hypotenuse} Tan\frac{Opposite}{Adjacent}


At the point/angle E:

- the adjacent side(side <u>next to</u> the point/angle) is ED

- the opposite side(side of the triangle <u>across</u> from the point/angle) is DF

- the hypotenuse (the<u> longest side</u> of the triangle) is EF.


sin ∠E = \frac{opposite}{hypotenuse}

sin ∠E = \frac{6}{10} = \frac{3}{5} (simplified)

5 0
3 years ago
Read 2 more answers
How do I find the area of a triangle with a base of 3 and height of 6
Schach [20]
You can multiply 3 and 6 together then divide the product by 2
(6*3)/2=18/2=9
6 0
3 years ago
PLEASE HELP ME WITH THIS!! ;(
DochEvi [55]

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4 0
2 years ago
Find all solutions of each equation on the interval 0 ≤ x &lt; 2π.
Korvikt [17]

Answer:

x = 0 or x = \pi.

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}.

\displaystyle \sec{x} = \frac{1}{\cos{x}}.

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, \sin^{2}{x} = 1 - \cos^{2}{x}. Therefore, for the square of tangents,

\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}.

This equation will thus become:

\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2.

To simplify the calculations, replace all \cos^{2}{x} with another variable. For example, let u = \cos^{2}{x}. Keep in mind that 0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1.

\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2.

\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2.

Solve this equation for u:

\displaystyle \frac{u^{2} + 1}{u^{2}} = 2.

u^{2} + 1 = 2 u^{2}.

u^{2} = 1.

Given that 0 \le u \le 1, u = 1 is the only possible solution.

\cos^{2}{x} = 1,

x = k \pi, where k\in \mathbb{Z} (i.e., k is an integer.)

Given that 0 \le x < 2\pi,

0 \le k.

k = 0 or k = 1. Accordingly,

x = 0 or x = \pi.

8 0
3 years ago
Read 2 more answers
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