Answer:
1.evaperation
2.condenstation
3.precipatation
Explanation:
So I guess condenstation leads to precipatation-
Answer:
1.02 × 10⁶ g
Explanation:
Step 1: Given data
- Volume of the balloon (V): 5400 m³
- Absolute pressure (P): 1.10 × 10⁵ Pa
- Molar mass of He (M): 4.002 g/mol
Step 2: Convert "V" to L
We will use the conversion factor 1 m³ = 1000 L.
5400 m³ × 1000 L/1 m³ = 5.400 × 10⁶ L
Step 3: Convert "P" to atm
We will use the conversion factor 1 atm = 101325 Pa.
1.10 × 10⁵ Pa × 1 atm / 101325 Pa = 1.09 atm
Step 4: Calculate the moles of He (n)
We will use the ideal gas equation.
P × V = n × R × T
n = P × V / R × T
n = 1.09 atm × 5.400 × 10⁶ L / 0.08206 atm.L/mol.K × 280 K
n = 2.56 × 10⁵ mol
Step 5: Calculate the mass of He (m)
We will use the following expression.
m = n × M
m = 2.56 × 10⁵ mol × 4.002 g/mol
m = 1.02 × 10⁶ g
Answer:
Yes
Explanation:
You add more force behind the cart with the higher mass. Assuming that its higher mass causes it to weigh more.
Answer: Option (B) is the correct answer.
Explanation:
When a fatty acid contains high number of double bonds then its unsaturation will also be high and hence, it will consume greater number of equivalents of hydrogen.
In corn oil, there are no unsaturated sites are present.
In olive oil, there is one unsaturated site with majority of oleic acid. In olive oil, there are more than 70% of total unsaturated oils.
In lard oil, there are around 60% of unsaturated oils.
In herring oil, there are highest number of saturated fatty acids and lowest polyunsaturated acids.
Thus, we can conclude that out of the given options, olive oils would consume the greatest number of equivalents of hydrogen when subject to catalytic hydrogenation.
