From the ideal gas equation, we know that PV = nRT
where, P = pressure, V = volume occupied, n = number of moles of gas, R = universal gas constant=0.082L atm mol-1 K-1 and T = temperature.
Given: P = 2.8 atm, V = 98 l and T = 292 k.
Therefore n = $\frac{PV}{RT}$ = $\frac{2.8 X 98}{0.082 X 292}$ = 11.46

6 0

3 years ago

How many molecules are in 1.5 moles of carbon dioxide

Karo-lina-s [1.5K]

Answer:

<h2>9.03 × 10²³ molecules</h2>

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 1.5 × 6.02 × 10²³

We have the final answer as

<h3>9.03 × 10²³ molecules</h3>

Hope this helps you

3 0

3 years ago