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mamaluj [8]
3 years ago
8

What actions affect blood pH

Chemistry
1 answer:
galben [10]3 years ago
4 0
Integestion, vomiting, diarrhea<span>, lung function, endocrine function, kidney function</span>
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The empirical formula for carbohydrates is CH2O. The molecular weight for a particular carbohydrate is 90.09 grams. What is the
baherus [9]
We find the weight of the empirical formula:
12.0107 + 2 x 1.00794 + 15.9994
= 30.03

Now, we divide the molecular weight by the weight of the empirical formula to find the number of times the empirical formula repeats:
90.09 / 30.03
= 3

The formula is 3(CH₂O)
C₃H₆O₃
6 0
3 years ago
Please answer this skskskskskksmsk
Sveta_85 [38]

Answer:see attached photo for answer

Explanation:cell division occurs to produce new cells from preexisting ones. the new cells are called daughter cells.the old cells are called parent cells.cell division may be mitosis or meiosis. Mitosis occurs in a somatic cell and produce four daughter cell. Meiosis occurs in sex cells and produce two daughter cells. Cell division usually involves Prophase, metaphase, anaphase and telophase.

Cell division occurs to ensure the continous existence of life.

Mitosis involve producing daughter cells with the same number of chromosomes as the parent cells while meiosis involves producing daughter cells with Half number of chromosomes.

4 0
3 years ago
Determine the mass of 2.75 moles of CaSO4. Record your work and your answer.
maw [93]

Explanation:

RFM \:  = 160 \: g \\ 1 \: mole \: weighs \: 160 \: g \\ 2.75 \: moles \: weighs \:  \frac{2.75 \times 160}{1} g \\  = 440 \: g

6 0
3 years ago
The reaction (CH3)3CBr + OH- (CH3)3COH + Br- in a certain solvent is first order with respect to (CH3)3CBr and zero order with r
son4ous [18]

Answer and Explanation:

The rate constant (K) is related to activation energy (Ea), frequency factor (A) and temperature (T) in Kelvin by the equation

R = molar gas constant

K = A(e^(-Ea/RT))

Taking natural log of both sides

In K = In A - (Ea/RT)

In K = (-Ea/R)(1/T) + In A

Comparing this to the equation of a straight line; y = mx + c

y = In K, slope, m = (-Ea/R), x = (1/T) and intercept, c = In A

a) From the question, m = (-Ea/R) = -1.10 × (10^4) K

(-Ea/R) = -1.10 × (10^4) = -11000

R = 8.314 J/K.mol

Ea = -11000 × 8.314 = 91454 J/mol = 91.454 KJ/mol

b) c = In A = 33.5

A = e^33.5 = (3.54 × (10^14))/s

c) K = A(e^(-Ea/RT))

A = (3.54 × (10^14))/s, Ea = 91454 J/mol, T = 25°C = 298.15 K, R = 8.314 J/K.mol

K = (3.54 × (10^14))(e^(-91454/(8.314×298.15))) = 0.0336/s

QED!

5 0
3 years ago
Which of the following statements are correct regarding the binding energy?
Andrews [41]
None of the above?
(Is there any statements?)
8 0
3 years ago
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