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kirza4 [7]
3 years ago
9

Please answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!

Mathematics
2 answers:
lapo4ka [179]3 years ago
4 0

Answer:

11,60,62

Hope this helps

irina1246 [14]3 years ago
3 0
What isn’t your the first time in the year you have a baby shower
You might be interested in
S
zzz [600]

Answer:

x = 4

Step-by-step explanation:

A trapezium is a quadrilateral (has four sides and four angles) with one pair of parallel sides. A trapezium is said to be isosceles if the bases are parallel, the two other sides known as the legs are equal and diagonals of the trapezium are equal to each other.

In trapezoid ABCD, BC and AD are the diagonals.

Hence BC = AD (property of isosceles trapezoid)

9x + 1 = 12x - 11

Simplifying:

12x - 9x = 1 + 11

3x = 12

Dividing both sides by 2:

x = 4

8 0
3 years ago
How do you write this equation x+5=2(7+x)
True [87]

Answer:

x=-9

Step-by-step explanation:

x+5=2(7+x)

x+5=14+2x

x-2x=14-5

-1x=9

x=-9

3 0
3 years ago
Read 2 more answers
Earth is approximately 9.3 × 107 miles from the sun. Saturn is approximately 8.87 × 108 miles from the sun. About how much farth
Nastasia [14]

Answer:

Both distances are in the scientific notation:

Earth - Sun = 9.3 * 10^7 miles

Saturn - Sun = 8.87 * 10^8 miles

8.87 * 10^8 - 9.3 * 10^7 =

= 88.7 *10^7 - 9.3 * 10^7 =

= 79.4 * 10^7 = 7.94 * 10 ^8 = 794,000,000 miles

Answer: Saturn is  7.94 * 10^8 miles farther from Sun than Earth is.

Step-by-step explanation:

I hope this helps you :)

-KeairaDickson

7 0
3 years ago
What is the factored form of 64g^3+8
vivado [14]
\bf \textit{difference and sum of cubes}
\\\\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3 
\\\\
a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad
(a-b)(a^2+ab+b^2)= a^3-b^3\\\\
-------------------------------\\\\
64g^3+8\implies 4^3g^3+8\implies (4g)^3+2^3
\\\\\\
(4g+2)[(4g)^2-(4g)(2)+2^2]\implies (4g+2)[(4^2g^2)-8g+4]
\\\\\\
(4g+2)(16g^2-8g+4)
3 0
3 years ago
If f(x)=4x^2 and g(x)=x+1, find (fog)(x)
iren [92.7K]

Answer: The value of (f_\circ g)(x)  is  4(x+1)^2  .

Step-by-step explanation:

Given: f(x) = 4x^2 \text { and } g(x) = x+1

To find: (f_\circ g)(x)

As we know it is composition function which means that  g(x) function is in f(x) function.

So we have

(f_\circ g) (x) =  f[g(x)]

\Rightarrow( f_\circ g)(x)= f(g(x)) = 4(g(x))^2

Now substitute the value of g(x) we get

(f_\circ g)(x)= 4(x+1)^2

Hence, the value of (f_\circ g)(x)  is  4(x+1)^2  .

5 0
4 years ago
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