<span>A calorie is a unit which is used to measure the amount of energy in a piece of food. In order to maintain their weight, a person needs to consume a fixed number of calories. A person that weighs 160 pounds needs to consume approximately 2080 calories if they are inactive, 2400 calories if they are moderately active and 2720 calories if they are very active. </span>
Kira's time exercising every day can be represented as t ≥ 40 because she exercises for 40 minutes or more.
<h3>How can this situation be represented?</h3>
This situation can be represented with an inequality. An inequality is an expression that is used to represent variables. This type of expression uses symbols such as >, < or ≥ to represent different variable values.
<h3>What inequality is represented in this situation?</h3>
- The expression is: t ≥ 40
The inequality represented in this situation implies that Kira exercises is equal or more time than 40 minutes every day.
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Ok so you find squares
example
we know ataht √9=3 becuase 9=3*3 so √9=√(3 times 3)=√(3^2) =3
so we factor 230
230=2 times 5 times 23
we do not have any doubles so this is simplest form
Answer:
37.5 acres.
Step-by-step explanation:
Fraction of his land where vegetables are grown
= 1 - 1/3 - 2/3 *3/5
(after taking away 1/3 we get 2/3 and the farmer uses 3/5 of this 2/3 to grow Maize.
= 1 - 1/3 - 6/15 LCD of 3 and 15= 15 so we write:
= 1 - 5/15 - 6/15
= 1 - (5+6)/16
= 1 - 11/15
= 4/15.
4 /15 is equivalent to 10 acres
so total area (= 1) = 10 / 4/15 Invert the 4/15 and multiply:
= 10 * 15/4
= 150/4
= 37.5 acres.
Answer:
Option 2 is right
Step-by-step explanation:
Given that
We can write this in polar form with modulus and radius
Hence angle = 60 degrees and
Since we have got 5 roots for z, we can write 60, 420, 780, etc. with periods of 360
Using Demoivre theorem we get 5th root would be
5th root of 2 multiplied by 1/5 th of 60, 420, 780,....
![z= \sqrt[5]{2} (cos12+isin12)\\z=\sqrt[5]{2} (cos84+isin84)\\\\z=\sqrt[5]{2} (cos156+isin156)\\\\z=\sqrt[5]{2} (cos228+isin228)\\\\z=\sqrt[5]{2} (cos300+isin300)\\](https://tex.z-dn.net/?f=z%3D%20%5Csqrt%5B5%5D%7B2%7D%20%28cos12%2Bisin12%29%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos84%2Bisin84%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos156%2Bisin156%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos228%2Bisin228%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos300%2Bisin300%29%5C%5C)
Out of these only 2nd option suits our answer
Hence answer is Option 2.
