Answer:
a) $520
b) $580
c) Interest amount is same each year
Step-by-step explanation:
Given - Georgie put $500 in her savings account, earning interest at a rate of 4% each year. She did not make any more deposits or withdrawals. 
To find - a) How much money was in the account after one year? 
               b) How much money was in the account after 4 years? 
               c) Was the amount of money earned in interest the same or different each year?
Proof -
Here given that,
Principal amount = $500
rate of interest = 4% = 4/100 = 0.04
Now,
a)
Amount =  P [ 1 + RT ]
              = 500 [ 1 + 0.04(1)]
              = 500 [ 1 + 0.04] = 520
⇒Amount = $520
b)
Amount =  P [ 1 + RT ]
              = 500 [ 1 + 0.04(4)]
              = 500 [ 1 + 0.16] = 580
⇒Amount = $580
c)
In 2nd year,
Amount =  P [ 1 + RT ]
              = 500 [ 1 + 0.04(2)]
              = 500 [ 1 + 0.08] = 540
⇒Amount = $540
Now,
Interest in 1st year = 520 - 500 = 20
Interest in 2nd year = 540 - 520 = 20
So,
The interest amount  is same each year
 
        
             
        
        
        
Answer:
A  =  $94652.66
Step-by-step explanation:
Use the compound amount formula   A = P(1 + r/n)^(nt), where r is the annual interest rate and n is the number of compounding periods per year.
Here, A = ($77000)(1 + 0.07/2)^(2*3), or
           A = $77000(1.035)^6, or
           A  =  $77000(1.229), or
            A  =  $94652.66
 
        
             
        
        
        
8-(6+2)+4 is how you use those numbers to equal 4
        
                    
             
        
        
        
Answer:
We need an image of the square.
Step-by-step explanation: