Answer:
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Hey there! I'm happy to help!
We want to find the probability that the player makes at least seven out of eight free throws. First, we find the probability of them making seven free throws.

Then, we find the probability of them making eight, which is another possibility that fits this.

Now, we add the probability of these two events happening.

Therefore, the probability that the player makes at least seven of eight free throws is 3/256 or about 1.17%
Have a wonderful day! :D
Answer:
3/4 x 2/2= 6/8
Step-by-step explanation:
multiply 3/4 x 2/2 to equal = 6/8
1: 40%
2: 30%
3: 20%
If we know one of the succeeded, then
1: 44.44%
2: 33.33%
3: 22.22%
If under the circumstance that they all fail to meet a strong leader, the board picks one of them at random,
1: 43.33%
2: 33.33%
3: 23.33%
The first person has a 2 in 5 chance of randomly getting a strong leader. If the first person doesn't find a strong leader, the second person has a 2/4 chance of getting a strong leader. If neither the first nor second person gets a strong leader, the third sales person has a 2/3 chance of getting a strong leader.
1: 2/5=40% Chance
2: (3/5)*(2/4)=30% Chance You have to take the probability the first rep failed to get a strong leader, then multiply by the probability the second rep gets a strong leader.
3: (3/5)*(2/4)*(2/3)=20% You have to take the probability both the other people failed, then multiply by the probability they succeeded.
Answer:
17% i think
Step-by-step explanation: