Simplify -tan(-x)cot(-x)
1 answer:
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Answer:
The answer is "Options A, B, and E represent mutually exclusive events".
Step-by-step explanation:
Two occurrences that can happen immediately called mutually incompatible. Let's now glance at our options and figure out where the statements are mutually incompatible events.
In Option A: You could see that landing on an unwanted portion and arriving on 2 are events that are locally incompatible, even as undesirable portion contains 3 and 4, and 2 were shaded.
In Option B: Arriving on a shaded part and falling on 3 are also mutually incompatible because there are 3 on a windows azure.
In Option C: A darkened portion and an increasing amount can land while 2 would be an even number as well as on the shaded portion. That number is very much the same.
In Option D: At the same time as 4 is greater than 3 and it is situated upon an undistressed section, landing and attracting a number larger than 3 can happen.
In Option E: Landing on a shaded part and landing on even a shaded part is an excluding event, since shaders may either be shaded or unlit.
Answer: Therefore, Option 'D' is correct.
Step-by-step explanation:
Since we have given that
Number of population = 132000
Number of voting districts = 11
According to question, no district is to have a population that is more than 10 percent greater than the population of any other district.
Let the number of population that the least populated district could have be 'x'.
So, it becomes,
Hence, there are 11000 population that the least populated district could have.
Therefore, Option 'D' is correct.