Yes, ode45 can be used for higher-order differential equations. You need to convert the higher order equation to a system of first-order equations, then use ode45 on that system.
For example, if you have
... u'' + a·u' + b·u = f
you can define u1 = u, u2 = u' and now you have the system
... (u2)' + a·u2 + b·u1 = f
... (u1)' = u2
Rearranging, this is
... (u1)' = u2
... (u2)' = f - a·u2 - b·u1
ode45 is used to solve each of these. Now, you have a vector (u1, u2) instead of a scalar variable (u). A web search regarding using ode45 on higher-order differential equations can provide additional illumination, including specific examples.
Answer:
1496.79 mm squared
Step-by-step explanation:
Have a good day :)
Answer:
square root (50) = 7.071
Step-by-step explanation:
Using Pthagoras' theorem, the diagonal length is .
Therefore, the diagonal length is the square root of 5^2+5^2,
=
=
= 7.071
- 4(20+22)
- 4(40+2)
This expression are equivalent to 4(42)
Answer: {y,x} = {4,2} ) ) ) )4
Step-by-step explanation: y
[2] y = -2x + 8
// Plug this in for variable y in equation [1]
[1] (-2x+8) - x = 2
[1] - 3x = -6
// Solve equation [1] for the variable x
[1] 3x = 6
[1] x = 2
// By now we know this much :
y = -2x+8
x = 2
// Use the x value to solve for y
y = -2(2)+8 = 4
Solution :
{y,x} = {4,2}