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Charra [1.4K]
2 years ago
10

What are the solutions of the quadratic equation?

Mathematics
2 answers:
Cloud [144]2 years ago
8 0
We have x^2 + 2 · x · (11/2) + (11/2)^2  = - 24 + (11/2)^2;
Then, ( x + 11/2 )^2 = -24 + 121/4;
( x + 11/2 )^2 + 96/4 - 121/4 = 0;
( x + 11/2 )^2 - 25 / 4 = 0;
( x + 11/2 )^2 - (5/2)^2 = 0;
( x + 11/2 - 5/2)·( x + 11/2 + 5/2 ) = 0;
( x + 6/2 )·( x + 16/2 ) = 0;
( x + 3 )· ( x + 8 ) = 0;
x = - 3 or x = -8;
The first choice is the correct answer.
sineoko [7]2 years ago
3 0
Original equation:  
x^2 + 11x = -24 
 Move everything to the left hand side of the equation. To do this, add 24 to each side.
 x^2 + 11x + 24 = 0 
 Now figure out a combination of two numbers that when added equals 11 but when multiplied equals 24. The answer is 8 and 3. 
 (x + 8)(x + 3) = 0 
 You can check the result by doing FOIL.
 There are two values for which the equation works: x = -8 and x = -3.
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If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a
harkovskaia [24]

Given:

The function is:

h(x)=x^2-3x+5

To find:

The value of h(2x+1).

Solution:

We have,

h(x)=x^2-3x+5

Putting x=2x+1, we get

h(2x+1)=(2x+1)^2-3(2x+1)+5

h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5

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On combining like terms, we get

h(2x+1)=4x^2+(4x-6x)+(1-3+5)

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Therefore, the required function is h(2x+1)=4x^2-2x+3.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=x%5E2-11x%2B24%3D0" id="TexFormula1" title="x^2-11x+24=0" alt="x^2-11x+24=0" align="absmiddle"
Mashcka [7]
Your answer is x=-24/11
8 0
3 years ago
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Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

6/6 = 1 gallon

12/6 = 2 gallons

12/6 - 7/6 = 5/6

5/6 should be the answer

5 0
3 years ago
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