Answer:
A
Step-by-step explanation:
![\left[\begin{array}{ccc}12 &-6\\1 &-10 \\\end{array}\right] +\left[\begin{array}{ccc}-2&14\\5&15\\\end{array}\right] =\left[\begin{array}{ccc}12-2&-6+14\\1+5&-10+15\\\end{array}\right] =\left[\begin{array}{ccc}10&8\\6&5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%20%26-6%5C%5C1%20%26-10%20%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%2614%5C%5C5%2615%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12-2%26-6%2B14%5C%5C1%2B5%26-10%2B15%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%268%5C%5C6%265%5C%5C%5Cend%7Barray%7D%5Cright%5D)
I don't see a list of options, but I know that the answer is y = -4x + 6.
Point - Slope Form: y - y₁ = m(x - x₁)
y - 2 = -4(x - 1)
y - 2 = -4x + 4
+ 2 + 2
--------------------
y = -4x + 6
(x^a)(x^b)=x^(a+b)
(ab)(cd)=(a)(b)(c)(d)
x^-m=1/(x^m)
(3y^-4)(2y^-4)=
(3)(y^-4)(2)(y^-4)=
(6)(y^-8)=
6/(y^8)
Answer:
a=1.29 approx
Step-by-step explanation:
3x6-10. The ten is supposed to be abive the six.
