I need help with my math, please help

Mathematics

2 answers:

miv72 [106K]2 years ago

5 0

Answer: x ≤ 6

Step-by-step explanation:

There are no more than 6 books in your bag, so the number of books in your bag is either exactly 6, or less than six, but no more than 6.

storchak [24]2 years ago

4 0

Answer:

x ≤6

Step-by-step explanation:

no more than means you can have 6 or less

x ≤6

You might be interested in

Please help with homework

Sedbober [7]

Ashley should get her seeds at garden place as she gets the exact amount of seeds and spends the least amount of money.
first of all I divided 75 by the amount of seeds you get it a packet. then if that was a decimal I rounded it to the larger number (eg. 7.15 rounded to 8)
then I multiplied the cost by that number to get the amount of money itd cost.
so I got in order of the boxes(s=seeds)
75s=$18
80s=$18.4
84s=$21.84
80s=$20
so the best deal is Garden place

7 0

3 years ago

The table displays the number of students in each grade at Richmond High School who will or will not be attending the amusement

Pani-rosa [81]

Answer:

$P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$

Step-by-step explanation:

We are given a joint probability table.

There are four different graders in a school

1. Grade Ninth

2. Grade Tenth

3. Grade Eleventh

4. Grade Twelfth

Field trip refers to the students who will attending the amusement park field trip.

No field trip refers to the students who will not be attending the amusement park field trip.

We want to find out the probability that the selected student is an eleventh grader given that the student is going on a field trip.

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)}$

Where P(eleventh and FT) is the probability of students who are in eleventh grade and will be going to field trip

$P(eleventh\: and \: FT) = \frac{13}{92} \\\\P(eleventh \: and \: FT) = 0.1413$

Where P(FT) is the probability of students who will be going to field trip

$P(FT) = \frac{12}{92} + \frac{9}{92} + \frac{13}{92} + \frac{19}{92}\\\\P(FT) = 0.1304 + 0.0978 + 0.1413 + 0.2065\\\\P(FT) = 0.576 \\\\$

So the required probability is

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)} \\\\P( eleventh\: \: |\: \: FT)= \frac{0.1413}{0.576} \\\\P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$