A graph shows the first comparison is true, and the C temperature is cooler than the F temperature for the remaining comparisons.
The comparison that is FALSE is ...
C.....30 °C is warmer than 90 °F
_____
30 °C = 86 °F
32.2 °C ≈ 90 °F
(4h+2)(2h+8)
4htines 2h= 8h^2
4htimes8=32h
2 times 2h=4h
2 times 8=16
Add Middle two you have
8h^2+36h+16
X=54 you do 331-7=324 the do 324/6=54 the end hope this helps
Answer:
Step-by-step explanation:
T(1)=1=0*x^3 0*x^2 0*x 1*1 T(x)=x-1=0*x^3 0*x^2 1*x (-1)*1 T(x^2)=2x^2-6x 6=0*x^3 2*x^2 (-6)*x 6 T(x^3)=6x^3-48*x^2 141*x-141 T(x^4)=24*x^3-204*x^2 628*x-604*1 collect the coefficient matrix and take its transpose
0 0 0 6 24
0 0 2 -48 -204
0 1 -6 141 628
1 -1 6 -141 -604