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2 years ago

Find the interest earned in an account with $600 invested at 4.5% annual simple interest for 2 years.

Mathematics

1 answer:

astra-53 [7]2 years ago

3 0

Answer:

40%

Step-by-step explanation:

every year the interested be 20%

that's why in 2 years be 40%interest

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Suppose you just purchased a digital music player and have put 10 tracks on it. After listening to them you decide that you like

OleMash [197]

Answer:

1/15 percent chance of that happening

Step-by-step explanation:

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2 years ago

A student selecting 3 classes for Winter quarter there are 4 drawing and design courses 3 general education courses and 3 other

pychu [463]

Answer:

36 possible class schedules

Step-by-step explanation:

1st - 4 ways

2nd - 3 ways

3rd - 3 ways

4 x 3 x 3 = 36 possible class schedules

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2 years ago

6x + 2x - 9 = 7<br> Solve the equation and simplify the answer

Tems11 [23]

Answer:

x=2

Step-by-step explanation:

6x+2x-9=7

Combine like terms on each side of the equation

8x-9=7

Add 9 to each side

8x=16

Divide by 8 on each side

x=2

8 0

2 years ago

Read 2 more answers

a bean plant was 15 centimeters tall one week ago. In 5 days it grew 1 meter. find the current height of the plant.

Likurg_2 [28]

The plant is currently 115 centimeters high

4 0

3 years ago

Find the area of the shaded region

o-na [289]

so hmmm let's get the area of the whole hexagon, and then get the area of the circle inside it, then <u>subtract the area of the circle from that of the hexagon's</u>, what's leftover is what we didn't subtract, namely the shaded part.

$\textit{area of a regular polygon}\\\\ A=\cfrac{1}{4}ns^2\cot\stackrel{\stackrel{degrees}{\downarrow }}{\left( \frac{180}{n} \right)}~ \begin{cases} n=\textit{number of sides}\\ s=\textit{length of a side}\\[-0.5em] \hrulefill\\ n=\stackrel{hexagon}{6}\\ s=\frac{9}{2} \end{cases}\implies A=\cfrac{1}{4}(6)\left( \cfrac{9}{2} \right)^2 \cot\left( \cfrac{180}{6} \right)$

$A=\cfrac{1}{4}(6)\cfrac{9^2}{2^2} \cot(30^o)\implies A=\cfrac{243}{8}\cot(30^o)\implies A=\cfrac{243\sqrt{3}}{8} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=\frac{4}{5} \end{cases}\implies A=\pi \left( \cfrac{4}{5} \right)^2\implies A=\cfrac{16\pi }{25} \\\\[-0.35em] ~\dotfill$

$\stackrel{\textit{area of the hexagon}}{\cfrac{243\sqrt{3}}{8}}~~ - ~~\stackrel{\textit{area of the circle}}{\cfrac{16\pi }{25}}\implies \cfrac{6075\sqrt{3}-128\pi }{200}$

5 0

1 year ago