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3 years ago

What a common mistake with bisect angles ?

Mathematics

1 answer:

ella [17]3 years ago

3 0

Answer:

Angle bisectors

Let’s first remember how to construct angle bisectors. First you draw a circle with center in a vertex of your angle and arbitral radius. From the points you got as intersections with your circle and arms of angle, you construct another two circles. Draw a semi line that goes through vertex and intersection of those two circles and you bisected your angle.

After knowing to construct angle bisector, people started wondering what would happen if they drew all three angle bisectors in a triangle. Will they intersect in the same point and what would that mean. So let’s try constructing it.

Step-by-step explanation:

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3 years ago

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Anna007 [38]

$h(-3) - h( - 2) = - \frac{5}{ 8} \\ \\$

Step-by-step explanation:

$\boxed{h(x) = \frac{2 {x}^{2} - x + 1}{3x - 2}}$

$h(2) = \frac{2 {(2)}^{2} - (2) + 1}{3(2) - 2}$

$h(2) = \frac{2 {(4)} - 2 + 1}{6 - 2}$

$h(2) = \frac{ 8 - 1}{4}$

$h(2) = \frac{7}{4}$

$h( - 3) = \frac{2 {( - 3)}^{2} - ( - 3) + 1}{3( - 3) - 2} \\ h( - 3) = \frac{2 (9) + 3 + 1}{ - 9- 2} \\ h( - 3) = \frac{18 + 4}{ - 11} \\ h( - 3) = \frac{22}{ - 11} \\ h(-3) = -2$

$h( - 2) = \frac{2 {( - 2)}^{2} - ( - 2) + 1}{3( - 2) - 2} \\ h( - 2) = \frac{2 (4) + 2+ 1}{- 6 - 2} \\ h( - 2) = \frac{8 + 3}{- 8} \\ h( - 2) = \frac{11}{- 8}$

$h(3) - h( - 2) = -2 - \frac{11}{- 8} \\ h(3) - h( - 2) =-2 + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-2}{1}+ \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16}{8} + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16+11}{8} \\ h(3) - h( - 2) = \frac{-5}{8} \\ - \frac{5}{ 8}$

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3 years ago

Please help!...<br> 1/2(4x-10)= -7<br> what does x equal?

professor190 [17]

Answer:

x=-1

Step-by-step explanation:

multiply both sides by 2

move the constant to the right

find the sum

then divide the 4 next to x

4 0

2 years ago

What a common mistake with bisect angles ?​

What a common mistake with bisect angles ?