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Nuetrik [128]
4 years ago
11

Energy waves moving through the air

Physics
2 answers:
sladkih [1.3K]4 years ago
7 0
Electromagnetic radiation
jasenka [17]4 years ago
3 0
Electromagnetic radiation waves:
They can be either infared radiation or visible light
We cannot see I fared radiation but it is how some energy is transferred
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ANSWER ASAP PLEASE!!
eimsori [14]
Sprry o cant see the words clearly
7 0
3 years ago
The force of the pulley is 652 newtons. It accelerates at 53 m/s. How much does the object weigh. a 1230 grams b 1.230 gram c 12
RoseWind [281]

Answer:

d. 12.30 grams

Explanation:

Given the following data;

Force = 652 N

Acceleration = 53 m/s²

To find how much the object weigh, we would need to determine its mass;

Force = mass * acceleration

652 = mass * 53

Mass = 652/53

<em>Mass = 12.30 grams.</em>

<em>Therefore, the object weighs 12.30 grams. </em>

5 0
3 years ago
A train of mass 5.6 × 10^5kg is at rest in a station.at time t=0s, a resultant force acts on the train and it starts to accelera
lana66690 [7]

Answer:

420000N

Explanation:

Given parameters:

Mass of the train  = 5.6 x 10⁵kg

Acceleration  = 0.75m/s²

Unknown:

Resultant force = ?

Solution:

According to newton's second law, force is the product of mass and acceleration;

   Force  = mass x acceleration

Resultant force that acts on the train is given below;

 Force  = 5.6 x 10⁵kg  x 0.75m/s²  = 420000N

7 0
3 years ago
Which of this following have the minimum frequency in their sound?
Verdich [7]

Answer:A MAN

Explanation:

5 0
3 years ago
One object has a charge of +5.0 · 10-6 c, and a second object has a charge of +2.0 · 10-6
ruslelena [56]
The electrostatic force between two charged objects is given by
F=k \frac{q_1 q_2}{r^2}
where
k is the Coulomb's constant
q1 is the charge of the first object
q2 is the charge of the second object
r is the separation between the two objects

In our problem:
q_1=+5.0 \cdot 10^{-6} C
q_2 = +2.0 \cdot 10^{-6} C
r=0.5 m
So if we plug these numbers into the equation, we can find the electrostatic force between the two objects:
F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(5.0 \cdot 10^{-6} C)(2.0 \cdot 10^{-6}C)}{(0.5 m)^2}=0.36 N
4 0
3 years ago
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