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3 years ago

Energy waves moving through the air

Physics

2 answers:

sladkih [1.3K]3 years ago

7 0

Electromagnetic radiation

jasenka [17]3 years ago

3 0

Electromagnetic radiation waves:
They can be either infared radiation or visible light
We cannot see I fared radiation but it is how some energy is transferred

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a 55.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 130 kg football players at a height of 0.800 m . the diamet

suter [353]

The diameter of the football player's piston is 0.55 m

Given that the mass of the cheerleader(m) is 55 kg, mass of football player to be hold (M) is 130 kg, height of the players (h) is 1.30 m, radius of the piston corresponding to the diameter (r) is 0.09 m, Diameter of football player's piston (R), P1 is Pressure on the cheerleader's side, P2 is Pressure on the football player's side

Using Pascal's law,

This law states that if there is a change at a point of a body immersed in a fluid then that change will spread thoroughly to each and every point of the body.

The formula of hydraulic system is,

P1= P2

F1/A1 = F2/A2

mg/πr^2 = 4Mg/πR^2

m/r^2=4M/R^2

R^2=4M×r^2/m

By plugging the values, we get.,

R^2=(4×130×0.09^2)/55

R^2=4.21/55=0.076

R=√0.076 = 0.275 m

Hence, diameter of football player's piston is 0.55 m

Learn more about Hydraulic lift here

brainly.com/question/19052774

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8 0

1 year ago

A 65 kg trampoline artist jumps vertically upward from the top of a platform with a speed of 5 m/s. how fast is he going as he l

KIM [24]

m = mass of trampoline artist = 65 kg

v₀ = initial speed of the artist at the top of platform = 5 $\frac{m }{s}$

h = height through which the artist drop before landing on trampoline = 3 m

v = final speed of the artist just before landing on trampoline = ?

using conservation of energy

Kinetic energy of artist just before landing = initial kinetic energy at the top of platform + potential energy at the top of platform

(0.5) m v² = (0.5) m v₀² + mgh

dividing each term by "m"

(0.5) v² = (0.5) v₀² + gh

inserting the values

(0.5) v² = (0.5) (5)² + (9.8)(3)

v = 9.2 $\frac{m }{s}$

x = compression of the trampoline = ?

k = spring stiffness constant = 62000 $\frac{N }{m}$

Assuming the lowest depression point as reference line for measuring the potential energy

using conservation of energy

kinetic energy of artist + potential energy of artist before landing = spring potential energy of trampoline

(0.5) m v² + mg x = (0.5) k x²

inserting the values

(0.5) (65) (9.2)² + (65 x 9.8) x = (0.5) (62000) x²

x = 0.31 m

6 0

3 years ago

How can you measure the strength of any electric field?

Softa [21]

Answer:

The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q.

Explanation:

Electric field strength is a vector quantity; it has both magnitude and direction. The magnitude of the electric field strength is defined in terms of how it is measured. Let's suppose that an electric charge can be denoted by the symbol Q. This electric charge creates an electric field; since Q is the source of the electric field, we will refer to it as the source charge. The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q. When placed within the electric field, the test charge will experience an electric force - either attractive or repulsive. As is usually the case, this force will be denoted by the symbol F. The magnitude of the electric field is simply defined as the force per charge on the test charge.

7 0

3 years ago

If two metal balls each have a charge of -10^-6 C and the repulsive force between them is 1 N, how far apart are they? (Coulomb'

Vitek1552 [10]

Answer:

The distance between the charges is 9.5 cm

(c) is correct option

Explanation:

Given that,

Charge $q= 10^{-6}\ C$

Force F = 1 N

We need to calculate the distance between the charges

Using Coulomb's formula

$F = \dfrac{kq_{1}q_{2}}{r^2}$

Where, q = charge

r = distance

F = force

Put the value into the formula

$1=\dfrac{9.0\times10^{9}\times(-10^{-6})^2}{r^2}$

$r=\sqrt{9\times10^{9}\times(-10^{-6})^2}$

$r=0.095\ m$

$r= 9.5\ cm$

Hence, The distance between the charges is 9.5 cm

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3 years ago

What was the average yearly ice loss in 1980 versus 2010?

matrenka [14]

In 1980 the average yearly ice loss found was -.05 whereas in the year of 2010 the average yearly ice loss found was -14. it is two hundred and eighty times greater than the average yearly ice loss in the year 1980.

7 0

4 years ago

Read 2 more answers