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4 years ago

Energy waves moving through the air

Physics

2 answers:

sladkih [1.3K]4 years ago

7 0

Electromagnetic radiation

jasenka [17]4 years ago

3 0

Electromagnetic radiation waves:
They can be either infared radiation or visible light
We cannot see I fared radiation but it is how some energy is transferred

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A particle moves along a straight path through displacement while force acts on it. (Other forces also act on the particle.) Wha

allsm [11]

a) c = 1.85

b) c = 0.8

c) c = 2.33

Explanation:

The displacement of the particle is given by

$d=2.2i+cj$

While the force applied on the particle is

$F=3.2i-3.8 j$

So we have a problem in 2-dimensions.

The work done on the particle is given by the scalar product between force and displacement:

$W=F\cdot d$ (1)

Here the work done on the particle is zero, so

W = 0

Therefore from eq(1) we find:

$0=(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=7.04\\c=\frac{7.04}{3.8}=1.85$

In this problem, the work done on the particle is

$W=4.0 J$

The force and displacement are still

$d=2.2i+cj$ (displacement)

$F=3.2i-3.8 j$ (force)

Therefore, by calculting the scalar product between force and displacement and equating it to the work done (4.0 J), we find:

$W=F\cdot d$

$4.0 =(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=3.04\\c=\frac{3.04}{3.8}=0.8$

In this problem instead, the work done on the particle is negative:

$W=-1.8 J$

As before, the force and displacement are

$d=2.2i+cj$ (displacement)

$F=3.2i-3.8 j$ (force)

And so again, we calculate the scalar product between force and displacement and we equate it to the work done on the particle, -1.8 J.

Doing so, we find:

$W=F\cdot d$

$-1.8=(3.2i-3.8j)\cdot (2.2i+c)=7.04-3.8c\\3.8c=8.84\\c=\frac{8.84}{3.8}=2.33$

7 0

3 years ago

Bob and Lily are riding on a typical carousel. Bob rides on a horse near the outer edge of the circular platform, and Lily rides

jekas [21]

Answer:

B.the same as Lily's.

Explanation:

When a disc is rotating on its axis uniformly with some angular velocity , every particle on it rotates with the same angular velocity , because every particle on it completes a rotation simultaneously . So in one rotation they take same time . Hence particles whether on the outer edge or near the axis , all have same angular velocity .

They but differ due to their different linear velocity . Linear velocity of particle near outer edge have greater magnitude. .

7 0

3 years ago

If the 15.0 cm string is shorter than the 30.0 cm string.

Margaret [11]

Answer:

option c) 2 is the right answer

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3 years ago

Why does the bottom of a swimming pool always appear shallower than it actually is<br>

emmainna [20.7K]

Answer:

The refraction of light at the surface of water makes ponds and swimming pools appear shallower than they really are.

Explanation:

so its just the refraction of light at the surface

8 0

3 years ago

Read 2 more answers

The force of gravity is an inverse square law. this means that, if you double the distance between two large masses, the gravita

likoan [24]

F~1/r²
doubling the distance r, Decreases the force by ¼

4 0

4 years ago