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Oksana_A [137]
2 years ago
8

Which is a device made from a coil of wire that carries a current and produces a magnetic field?

Physics
2 answers:
slega [8]2 years ago
8 0
A device made from a coil of wire that carries a current and produces a magnetic field is called a <span>solenoid. </span><span>✅
</span><span>
Answer: Letter B

Hope that helps. -UF aka Nadia</span>
sattari [20]2 years ago
7 0
The answer is B.) A solenoid. Hope it helps! :) 
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Kruka [31]
Velocity includes direction, for instance going 140 MPH is speed but going 140 MPH North is velocity
5 0
2 years ago
Read 2 more answers
The rubber band contains .......potential energy as it is stretched.
kodGreya [7K]

Answer:

elastic potential energy

You input potential (stored) energy into the rubber band system when you stretched the rubber band back. Because it is an elastic system, this kind of potential energy is specifically called elastic potential energy.

Explanation:

4 0
1 year ago
two point charges of 3.4 μc and 6.6 μc are 0.20 m apart. what is the electrical potential energy of the system?
Daniel [21]

Explanation:

electrical potential = (6.6-3.4)/0.20

= 16 uc/m

8 0
2 years ago
A solid circular shaft and a tubular shaft, both with the same outer radius of c=co = 0.550 in , are being considered for a part
Norma-Jean [14]

Answer:

The power for circular shaft is 7.315 hp and tubular shaft is 6.667 hp

Explanation:

<u>Polar moment of Inertia</u>

(I_p)s = \frac{\pi(0.55)4}2

      = 0.14374 in 4

<u>Maximum sustainable torque on the solid circular shaft</u>

T_{max} = T_{allow} \frac{I_p}{r}

         =(14 \times 10^3) \times (\frac{0.14374}{0.55})

         = 3658.836 lb.in

         = \frac{3658.836}{12} lb.ft

        = 304.9 lb.ft

<u>Maximum sustainable torque on the tubular shaft</u>

T_{max} = T_{allow}( \frac{Ip}{r})

          = (14 \times10^3) \times ( \frac{0.13101}{0.55})

          = 3334.8 lb.in

          = (\frac{3334.8}{12} ) lb.ft

          = 277.9 lb.ft

<u>Maximum sustainable power in the solid circular shaft</u>

P_{max} = 2 \pi f_T

          = 2\pi(2.1) \times 304.9

          = 4023.061 lb. ft/s

          = (\frac{4023.061}{550}) hp

          = 7.315 hp

<u>Maximum sustainable power in the tubular shaft</u>

P _{max,t} = 2\pi f_T

            = 2\pi(2.1) \times 277.9

            = 3666.804 lb.ft /s

            = (\frac{3666.804}{550})hp

            = 6.667 hp

7 0
3 years ago
Just wanna make sure im right
NikAS [45]
It is right have a good day

explanation step by step
6 0
3 years ago
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