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Oksana_A [137]
3 years ago
8

Which is a device made from a coil of wire that carries a current and produces a magnetic field?

Physics
2 answers:
slega [8]3 years ago
8 0
A device made from a coil of wire that carries a current and produces a magnetic field is called a <span>solenoid. </span><span>✅
</span><span>
Answer: Letter B

Hope that helps. -UF aka Nadia</span>
sattari [20]3 years ago
7 0
The answer is B.) A solenoid. Hope it helps! :) 
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The Answer is C. the distance light travels in a year
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vodka [1.7K]

Answer:

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A stone is dropped at t = 0. A second stone, with 6 times the mass of the first, is dropped from the same point at t = 59 ms. (a
xxTIMURxx [149]

Answer:y_{com}=0.707 m

v_{com}=3.713 m/s

Explanation:

Given

first stone mass is m

second stone mass is 6 m

distance traveled by  first stone in 430 ms

y_1=ut+\frac{at^2}{2}

y_1=0+\frac{g(0.43)^2}{2}

y_1=0.9069 m

Distance traveled by stone 2 in t=430-59=371 ms

y_2=ut+\frac{at^2}{2}

y_2=0+\frac{g(0.0.371)^2}{2}

y_2=0.674 m

velocity of first stone after t=0.43 s

v_1=u+at

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velocity of second stone after t=0.371 s

v_2=u+at

v_2=0+9.8\times 0.371=3.63 m/s

Position of Center of mass of system

y=\frac{y_1m_1+y_2m_2}{m_1+m_2}

y=\frac{0.9069\times m+0.674\times 6m}{m+6m}

y=\frac{4.95m}{7m}=0.707 m

Velocity of COM

v_{com}=\frac{v_1m_1+v_2m_2}{m_1+m_2}

v_{com}=\frac{4.214\times m+3.63\times 6m}{m+6m}

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6 0
4 years ago
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dimaraw [331]

You skipped over a number in the question, and you didn't tell me what my average speed is. Lucky for you, my average speed has NO EFFECT on the answer to the question.

When you calculate velocity, you only use the straight-line distance between the start-point and the end-point. It doesn't matter what route the thing took to get there, or how much ground it actually covered.

If I travel in a circle and stop at the same point I started from, then the size of the circle doesn't matter, and neither does my speed. The distance between my start-point and my end-point is zero, and my average velocity is zero.

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I think so..

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