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r-ruslan [8.4K]

3 years ago

8

Using the human species as an example, explain why physical appearance or morphology is NOT always useful for identifying organi

sms belonging to the same species.

1 answer:

Elenna [48]3 years ago

8 0

Answer:

Get SNS

Explanation:

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Help i have no idea what i’m doing and i’m failing this class

m_a_m_a [10]

Answer:

c

Explanation:

esuba is activation energy

8 0

3 years ago

What are the electrons called in the lectrons called in the outermost energy level of an atom? Why are they important (10) (B) T

koban [17]

Answer:

This outermost shell is known as the valence shell, and the electrons found in it are called valence electrons.

Explanation:

They are important to an atom because the fewer valence electrons that the atom holds, the less stable it becomes.

6 0

3 years ago

A student weighs 0.347 g of KHP on a laboratory balance. The KHP was titrated with NaOH and the concentration of the NaOH determ

V125BC [204]

Answer:

Following are the solution to the given question:

Explanation:

Each method through KHP is somewhat more precise since we have weighed that requisite quantity, we exactly know the KHP intensity appropriately. Its initial 6 M HCl concentration was never considered mandatory. They have probably prepared 6 M HCl solution although long ago and could have changed its concentration over even a period.

3 0

3 years ago

A student pours 10.0 g of salt into a container of water and observes the amount of time it takes for the salt to dissolve. She

9966 [12]

Answer:

It will go faster each time because she is stirring therefore the water can get to the salt faster than it just sitting at the top

Explanation:

6 0

3 years ago

How many grams of sodium chromate, Na2CrO4, are needed to react completely with

JulsSmile [24]

Answer:

We need 27.0 grams of Na2CrO4 to react with 56.7 grams of AgNO3

Explanation:

Step 1: data given

Mass of silver nitrate AgNO3 = 56.7 grams

Molar mass AgNO3 = 169.87 g/mol

Molar mass of Na2CrO4 = 161.97 g/mol

Step 2: The balanced equation

2AgNO3 + Na2CrO4 → Ag2CrO4 + 2NaNO3

Step 3: Calculate moles AgNO3

Moles AgNO3 = mass AgNO3 / molar mass AgNO3

Moles AgNO3 = 56.7 grams / 169.87 g/mol

Moles AgNO3 = 0.334 moles

Step 4: Calculate moles Na2CrO4 moles needed

For 2 moles AgNO3 we need 1 mol Na2CrO4 to produce 1 mol Ag2CrO4 and 2 moles NaNO3

For 0.334 moles AgNO3 we need 0.334 / 2 = 0.167 moles Na2CrO4

Step 5: Calculate mass Na2CrO4

Mass Na2CrO4 = 0.167 moles * 161.97 g/mol

Mass Na2CrO4 = 27.0 grams

We need 27.0 grams of Na2CrO4 to react with 56.7 grams of AgNO3

8 0

3 years ago