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4 years ago

Explain what would happen if an electron and a proton were brought near each other and then released. why would this happen?

Chemistry

1 answer:

Leni [432]4 years ago

3 0

They would repel one another because they they have opposing charges

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Name one gas that can form when the carbon in coal burns! And describe its harmful effects

nalin [4]

Coal is mainly made of carbon and there’s oxygen in the air so this burns to produce carbon dioxide. Breathing it can really hurt your lungs.

4 0

3 years ago

Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2H2S(g) 3O2(g)2H2O(l) 2SO2

Marizza181 [45]

Answer:

$\Delta _rH=-1124.14kJ/mol$

Explanation:

Hello!

In this case, since the standard enthalpy change for a chemical reaction is stood for the enthalpy of reaction, for the given reaction:

$2H_2S(g) +3O_2(g)\rightarrow 2H_2O(l) +2SO_2(g)$

We set up the enthalpy of reaction considering the enthalpy of formation of each species in the reaction at the specified phase and the stoichiometric coefficient:

$\Delta _rH=2\Delta _fH_{H_2O,liq}+2\Delta _fH_{SO_2,gas}-2\Delta _fH_{H_2S,gas}-3\Delta _fH_{O_2,gas}$

In such a way, by using the NIST database, we find that:

$\Delta _fH_{H_2O, liq}=-285.83kJ/mol\\\\\Delta _fH_{SO_2, gas}=-296.84kJ/mol\\\\\Delta _fH_{O_2,gas}=0kJ/mol\\\\\Delta _fH_{H_2S,gas}=-20.50kJ/mol$

Thus, we plug in the enthalpies of formation to obtain:

$\Delta _rH=2(-285.73kJ/mol)+2(-296.84kJ/mol)-2(-20.50kJ/mol)-3(0kJ/mol)\\\\\Delta _rH=-1124.14kJ/mol$

Best regards!

8 0

3 years ago

6. How is energy transferred to the earth?I

qaws [65]

Answer:

Energy is transferred between the earths surface and atmosphere.Energy move place to place

8 0

3 years ago

How many ammonium ions and how many sulfate ions are present in an 0.250 mol sample of (nh42so4?

Nastasia [14]

Thw answer is PHj78 JJ CP30 R2D2

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3 years ago

An elastic cord can be stretched to its elastic limit by a load of 2N.If a 35cm length of the cord is extended 0.6cm by a force

Levart [38]

Explanation:

$from \: hookes \: law \\ F = k.e \\ but \: e = 0.6 \: cm \\ 2 = k \times 0.6 \\ k = 3.33 \\ when \:F \: is \: 2.5 \\ 2.5 = 3.33 \times e {}^{.} \\ {e}^{. } = 0.75 \: cm \\ new \: length = 35 - {e}^{.} \\ = 35 - 0.75 \\ = 34.25 \: cm$

3 0

3 years ago