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Gre4nikov [31]
3 years ago
7

The equation of a circle is (x - 3)^2 + (y - 1)^2 = 64. Find the equation of the circle after it is shifted 2 units to the right

and 4 units up. * 2 points
Mathematics
1 answer:
torisob [31]3 years ago
8 0

Answer:

(x-5)²+(y-5)²=64.

Step-by-step explanation:

When it comes to shifting, we simply need to change the vertex of the equation. Remember that the formula for a circle is:

(x-h)²+(y-k)²=r²---- (h,k) being the vertex.

In this case, h=3 and k=1. We are also shifting 2 units to the right, meaning we need to subtract 2 from the 'h' value. A shift of 4 units up means we have to subtract 4 from the 'k' value.

Our new equation is:

(x-5)²+(y-5)²=64.

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Solve the following system of equations. Enter the y-coordinate of the solution. Round your answer to the nearest tenth.
Alex17521 [72]
-2x + 6y = -34
-x + 3y = -17
x = 3y +17

Sub this into 1st eqn
5(3y + 17) + 2y = 21
15y + 85 + 2y =21
17y = -64
y = -3.7647 (to 5 sig. fig.)
y = -3.8 (to nearest tenth)

Sub y = -3.7647 into 2nd eqn
x = 3(-3.7647) +17
x = 5.7 (to nearest tenth)
7 0
3 years ago
25) Wal-Mart is having a sale on packs of pencils. A pack of 24 pencils is on sale for $0.48. I plan to buy 20 packs of pencils.
Bezzdna [24]
Multiply the 20 packs by the 0.48 per pack
Your answer will be $9.60
4 0
3 years ago
Read 2 more answers
Solve<br>0.9(7x + 14) = 1.5 - (x + 2)
Triss [41]

\\ \sf\longmapsto 0.9(7x+14)=1.5-(x+2)

\\ \sf\longmapsto 6.3x+12.6=1.5-x-2

\\ \sf\longmapsto 63x+12.6=-x-0.5

\\ \sf\longmapsto 63x+x=-0.5-12.6

\\ \sf\longmapsto 64x=-13.1

\\ \sf\longmapsto x=\dfrac{-13.1}{64}

\\ \sf\longmapsto x=0.2

7 0
3 years ago
The manufacturer of hardness testing equipment uses​ steel-ball indenters to penetrate metal that is being tested.​ However, the
kumpel [21]

Answer:

Check the explanation

Step-by-step explanation:

Let X denotes steel ball and Y denotes diamond

\bar{x_1} = 1/9( 50+57+......+51+53)

=530/9

=58.89

\bar{x_2}= 1/9( 52+ 56+....+ 51+ 56)

=543/9

=60.33

difference = d =(60.33- 58.89)

=1.44

s^2=1/n\sum xi^2 - n/(n-1)\bar{x}^2

s12 = 1/9( 502+572+......+512+532) -9/8 (58.89)2

=31686/8 - 9/8( 3468.03)

=3960.75 - 3901.53

=59.22

s1 = 7.69

s22 = 1/9( 522+ 562+....+ 512+ 562) -9/8 (60.33)2

=33295/8 - 9/8 (3640.11)

=4161.875 - 4095.12

=66.75

s2 =8.17

sample standard deviation for difference is

s=\sqrt{[(n1-1)s_1^2+ (n2-1)s_2^2]/(n1+n2-2)}

 = \sqrt{[(9-1)*59.22+ (9-1)*66.75]/(9+9-2)}

= \sqrt{1007.76/16}

=7.93

sd = s*\sqrt{(1/n1)+(1/n2)}

=7.93*\sqrt{(1/9)+(1/9)}

=7.93* 0.47

=3.74

For 95% confidence level Z (\alpha /2) =1.96

confidence interval is

d\pm Z(\alpha /2)*s_d

=(1.44 - 1.96* 3.75 , 1.44+1.96* 3.75)

=(1.44 - 7.35 , 1.44 + 7.35)

=(-2.31, 8.79)

There is sufficient evidence to conclude that the two indenters produce different hardness readings.

3 0
3 years ago
If cos -105º = -0.26 and csc -105º = -1.03, then cos 105º = and csc 105º = .
andreyandreev [35.5K]

Answer:

cos (105°) = - 2.6

csc (105°) = 1.03

Step-by-step explanation:

Given that cos (-105°) = - 0.26 {The negative sign is due to the angle - 105° lies in the third quadrant where cos value is negative}

Again, given that csc (- 105°) = - 1.03 {{The negative sign is due to the angle - 105° lies in the third quadrant where csc value is negative}

Now, cos (105°) = - 2.6, because 105° lies in the second quadrant and here cos value is negative.

And csc (105°) = 1.03, because 105° lies in the second quadrant and here csc value is positive. (Answer)

3 0
3 years ago
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