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drek231 [11]
3 years ago
14

Please I need some answers

Mathematics
2 answers:
jek_recluse [69]3 years ago
5 0
A) = 2
B) = -1
C) = -1

Explanation:
jekas [21]3 years ago
3 0
A. -1 B. -1 C. -4 Hope this helps
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Madison makes 7 out of 12 free-throws. If she continues at the same rate, how many will she make if she shoots 156 free-throw
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Step-by-step explanation:

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2 years ago
What is the equation of 1/2x =5/6
LekaFEV [45]

Step-by-step explanation:

\frac{1}{2}x =  \frac{5}{6}

2 \times  \frac{1}{2}x = 2 \times  \frac{5}{6}

x =  \frac{5}{3}

4 0
3 years ago
Figure out the two- step equation please i NEED HELLLP! <br> -5c - 15 = -35
mariarad [96]

Answer:

c=4

Step-by-step explanation:

-5c - 15 = -35

Add 15 to each side

-5c - 15+15 = -35+15

-5c = -20

Divide each side by -5

-5c/-5 = -20/-5

c = 4

8 0
3 years ago
Read 2 more answers
Explain how to subtract the polynomial (The first attachment) from (The second attachment)
Salsk061 [2.6K]
(5x^3-3x-6)-(4x^3+7x+1)\\\\=5x^3-3x-6-4x^3-7x-1\\\\=(5x^3-4x^3)+(-3x-7x)+(-6-1)\\\\=x^3+(-10x)+(-7)\\\\=\boxed{x^3-10x-7}
5 0
3 years ago
Billy is monitoring the exponential decay of a radioactive compound. He has a sample of the compound in a test tube in his lab.
Over [174]

Solution:

Formula for radioactive Decay is given by

R_{0}= R(1-\frac{S}{100})^t

R_{0}= Initial Population

R = Remaining population after time in hours

Rate of Decay = S % per hour

Initial Population = 72 grams

Final population = 15 grams

Rate of Decay = 35 % per hour

Substituting the values to get value of t in hours

72=15(1-\frac{35}{100})^t\\\\ 4.8= (0.65)^t\\\\ t= -3.64→→1 St expression

But taking positive value of t , that is after 3.64 hours the sample of 72 grams decays to 15 grams at the rate of 35 % per hour.

Now , it is also given that, Once the sample reaches a mass of 15 grams, Billy will continually add more of the compound to keep the sample size at a minimum of 15 grams.

Substituting these in Decay Formula

Final Sample = 15 gm

Starting Sample = 15 +k, where k is amount of sample added each time to keep the final sample to 15 grams.

Time is over 3.64 hours i.e new time = 3.64 + t

Rate will remain same i.e 35 % per hour.

15=(15+k)(1-\frac{35}{100})^{3.64+t}→→→  Final expression (Second) , that is inequalities can be used to determine the possible mass of the radioactive sample over time.







5 0
3 years ago
Read 2 more answers
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