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Natasha2012 [34]
2 years ago
6

Simplify

Mathematics
1 answer:
blagie [28]2 years ago
8 0
-6-7(c+10)
-6-7c-70
-76-7c
B
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I suck at algebra but my advice is download photomath it will help trust me
7 0
3 years ago
A radioactive substance decays at a continuous rate of 12% per year, and 90 mg of the substance is present in the year 2000. (a)
Alla [95]

Answer:

A(t) = 90e^0.12t ;

299 mg

Step-by-step explanation:

General Continous growth rate equation :

A = Pe^rt

A = amount present, t years after year of initial amount.

Here,

P = 90 mg, amount in year 2000

r = rate = 12% = 0.12

t = years after 2000

Therefore,

A is written as ;

A(t) = 90e^0.12t

Amount present in year 2010 ;

t = 2010 - 2000 = 10

A(10) = 90e^0.12(10)

A(10) = 90 * e^1.2

= 90 * 3.3201169

= 298.81052

= 299 mg

5 0
2 years ago
Given f(x) = 4x + 2, find f-1(3).
Alexxandr [17]

Answer:

  1/4

Step-by-step explanation:

The inverse function tells you the input value that corresponds to the given output value of the function.

<h3>Application</h3>

You want f^-1(3), which is the value of x such that f(x) = 3.

  f(x) = 3 = 4x +2

  1 = 4x . . . . . . subtract 2

  1/4 = x . . . . . divide by 4

The inverse function of 3 is 1/4:

  \boxed{f^{-1}(3)=\dfrac{1}{4}}

4 0
2 years ago
Help please...........-
vovangra [49]

Answer:c

Step-by-step explanation:

c

8 0
2 years ago
Read 2 more answers
Help please look below
Gwar [14]
A is located, as you look A is past -2 almost hitting -3 making the mark 2.8 so the answer is A
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2 years ago
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