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posledela
3 years ago
13

One of the longest tapeworms ever measured was five feet less than six times the length of the longest roundworm ever measured.

If you laid these two worms end to
end, they would measure an amazing 79 feet! How long was the tapeworm and how long was the roundworm?
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
5 0
She a runner she a track start
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9 x 7 = ( x 7) – (1 x 7)<br> = 70-<br> =
WARRIOR [948]

Answer:

63

Step-by-step explanation:

9x7=(10x7)-1x(7)

=70-7

=63

8 0
3 years ago
Dany has a business selling bracelets for 7.50 each. She only has enough material to make 5 bracelets. If x represents the numbe
ziro4ka [17]

Answer:

The range is [0,37.5]

Step-by-step explanation:

We start by writing the equation that links x and y

From the question;

y = 7.5x

Now, she has enough material to make 5 only

When we talk of range, we are referring to the values on the y-axis

So the lowest y value is 0

and since the highest number of bracelets is 5;

The total cost of the 5 is 7.5(5) = 37.5

So the range is [0,37.5]

6 0
3 years ago
PLEASE HELP Which expression represents the difference quotient of the function f (x) = negative StartRoot 2 x EndRoot?
natali 33 [55]

Answer:

c is the correct option

Step-by-step explanation:

from,

f'(x) = h >0 <u>f</u><u>(</u><u>x</u><u> </u><u>+</u><u> </u><u>h</u><u>)</u><u> </u><u>-</u><u> </u><u>f</u><u>(</u><u>x</u><u>)</u><u> </u>

h

f(x) = - √2x

f(x + h) = - √(2x + h)

f'(x) = h>0 <u>-</u><u>√(2x + h) - √2x</u>

h

rationalize the denominator

= h>0 <u>-</u><u>√</u><u>(</u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>h</u><u>)</u><u> </u><u>+</u><u> </u><u>√</u><u>2</u><u>x</u><u> </u><u> </u><u>(</u><u>-</u><u>√</u><u>(</u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>h</u><u>)</u><u> </u><u>-</u><u> </u><u>√</u><u>2</u><u>x</u><u>)</u>

h (-√(2x + h) - √2x)

= h>0 <u>4</u><u>x</u><u> </u><u>+</u><u> </u><u>2</u><u>h</u><u> </u><u>-</u><u> </u><u>4</u><u>x</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

h(-√(2x + h) -√2x)

= h>0 <u>2</u><u>h</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

h(-√(2x+h) - √2x)

= h>0 <u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>2</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

-√(2x+h) - √2x

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