Use the gcf to factor: 6e+24n

Sam is hired for a 20-day period. On days that he works, he earns $60. For each day that he does not work, $30 is subtracted fro

Alenkinab [10]

Answer:

He did not work for 6 days

Step-by-step explanation:

Sam is hired for a 20-day period.

Let x be the no. of days he did not work

So, No. of days he worked = 20-x

he earns per working day = $60

So, he earns for (20-x) days = 60(20-x)

For each day that he does not work, $30 is subtracted from his earnings.

So, Amount deducted for x days = 30x

So, His earning for 20 days = $60(20-x)-30x$

We are given that At the end of the 20-day period, he received $660

So, $60(20-x)-30x=660$

$1200-60x-30x=660$

$1200-90x=660$

$1200-660=90x$

$540=90x$

$\frac{540}{90}=x$

$6=x$

So, he did not work for 6 days

So, Option C is true

5 0

3 years ago

HURRY!!!! I need help with this asap!!!!!

Nina [5.8K]

Answer:

380,160 and 2nd one should be 240

Step-by-step explanation:

6 0

3 years ago

Select "ALL" statements that correctly describe the graph!!

larisa86 [58]

Answer:

The slope is 1/2
The equation that represents this function is x -2y = 2

Step-by-step explanation:

Intercepts

The table shows the x-intercept to be (2, 0), and the y-intercept to be (0, -1). These are not matched by any of the answer choices.

Slope

The slope is ...

slope = (change in y)/(change in x) = (0 -(-1))/(2 -0) = 1/2

Equation

You can choose the equation by seeing if it works for a couple of points. You know the last equation is incorrect, because that slope-intercept form has the y-intercept as +1, not -1.

6 0

2 years ago

A hypothesis test is conducted at the .05 level of significance to test whether or not the population correlation is zero. If th

finlep [7]

Answer:

Th computed value of the test statistic is 3.597

Step-by-step explanation:

The null and the alternative hypothesis is as follows:

Null Hypothesis:

$\mathbf{H_o:}$ the population correlation coefficient is equal to zero

$\mathbf{H_a:}$ the population correlation coefficient is not equal to zero

The test statistics for Pearson correlation coefficient is thus computed as :

$t =\dfrac{r \sqrt{(n-2)}} { \sqrt{(1-(r)^2)} }$

where;

r = correlation coefficient = 0.60

n = sample size = 25

So;

$t =\dfrac{0.60 \sqrt{(25-2)}} { \sqrt{(1-(0.60)^2)} }$

$t =\dfrac{0.60 \sqrt{(23)}} { \sqrt{(1-0.36} }$

$t =\dfrac{0.60 *4.796} {0.8}$

t = 3.597

Comparing to a critical value of t (23 degrees of freedom two-tailed value) = 2.069

Decision Rule:

Since computed value of t is greater than the critical value of t; We reject the null hypothesis and accept the alternative hypothesis.

Conclusion:

We conclude that the population correlation coefficient significantly differs from 0 at 5% (0.05) level of significance.

6 0

3 years ago

Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu

Softa [21]

Answer-

The polynomial function is,

$y=x^4-10x^3+38x^2-64x+40$

Solution-

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

$\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))$ ( ∵ (3-i) is the conjugate of (3+i) )

$\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)$

$\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)$

$\Rightarrow y=(x^2-4x+4)(x^2-6x+10)$

$\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10$

$\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40$

$\Rightarrow y=x^4-10x^3+38x^2-64x+40$

Therefore, this is the required polynomial function.

4 0

3 years ago

Use the gcf to factor: 6e+24n​

Use the gcf to factor: 6e+24n