What is the simplified form of V 100x35 ?

Nicole is going to see a movie and is taking her 3 kids. Each movie ticket costs $14 and there are an assortment of snacks avail

Andrews [41]

Answer:

Four tickets and four snacks comes to a total of $74.00

If she buys x snacks, that cost is 4.50x. so the total for 4 tickets and unknown snacks is 4(14) + 4.5x

Step-by-step explanation:

Nicole + 3 kids is 4 tickets times $14. 4×14=56. Add the snacks. 4×4.50=18. $56+$18=$74

5 0

3 years ago

Find each. a. za_2 for the 99% confidence interval b. za_2 for the 98% confidence interval c. za_2 for the 95% confidence interv

irga5000 [103]

Answer:

a) Z = 2.575.

b) Z = 2.327.

c) Z = 1.96.

d) Z = 1.645.

e) Z = 1.88.

Step-by-step explanation:

Question a:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.99}{2} = 0.005$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.005 = 0.995$ , so Z = 2.575.

Question b:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.98}{2} = 0.01$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.01 = 0.99$ , so Z = 2.327.

Question c:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Question d:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Question e:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.94}{2} = 0.03$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.03 = 0.97$ , so Z = 1.88.

8 0

3 years ago

What is the value of b?

docker41 [41]

Do do this problem, you need to use the Law of Cosines!

You are trying to find length b, so

b^2 = a^2 + c^2 - 2ab cos B
b^2 = 22^2 + 28^2 - 2(22)(28) cos 34
b^2 = 484 + 784 - 1232 cos 34
b^2 = 1268 - 1232 cos 34
b^2 = 246.6257
b = 15.7 yards

Hope this helps!

3 0

4 years ago

Read 2 more answers

If you pop 3 bags of popcorn in 15 minutes how many bags did you pop per minute

Harman [31]

1 for every 5 minutes

7 0

4 years ago

Read 2 more answers

What is the answer to this ? I totally forgot how to this kind of math 5/7 x 1/2

notka56 [123]

Answer: