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ArbitrLikvidat [17]
3 years ago
6

Kristen is making accessories for the soccer team. She uses 595.56 inches of fabric on headbands for 39 players and 3 coaches. S

he also uses 343.59 inches of fabric on wristbands for just the players. How much fabric was used on a headband and wristband for each player?
Mathematics
1 answer:
11111nata11111 [884]3 years ago
3 0

Answer:

22.99 inches

Step-by-step explanation:

According to problem, given data are as follows:

Fabric used for headband = 595.56 inches

Number of headbands made = 39 + 3 = 42

So, Fabric used per headband = 595.56 ÷ 42 = 14.18 inches per headband

Similarly, Fabric used for wristband = 343.59 inches

Number of wristbands made = 39

So, Fabric used per wristband = 343.59 ÷ 39 = 8.81 inches per wristband

So, Fabric used for each player = 14.18 inches + 8.81 inches

= 22.99 inches

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Sam and Bruno were computing how many kilometers they rode in the 3 bike trips they took last month. In order, they rode 45.7, 4
Eddi Din [679]

Answer:

We are given number of miles the 3 bike trips they took last month = 45.7, 40.9, and 38 miles.

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Also one kilometer equals 0.621 miles.

From this we can see than 1 kilometer is smaller unit and a mile is a larger unit.

In order to convert number of miles into kilometers, we need to divide each number of mile by 0.621 miles.

We always divide a larger value by a smaller value to get the smaller unit.

Therefore,

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Step-by-step explanation:

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4 0
3 years ago
A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a
sdas [7]

Answer:

y=-\dfrac{13}{49}x^2

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

y=ax^2+bx+c

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

-13=a(-7)^2+b(-7)+c

49a-7b+c=-13

(x,y) = (7,-13)

-13=a(7)^2+b(7)+c

49a+7b+c=-13

(x,y) = (0,0)

0=a(0)^2+b(7)+c

c=0

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13

49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13

we can solve these two equation using the elimination method, by simply adding the two equations

\quad\quad49a-7b=-13\\+\quad49a+7b=-13

------------------------------

\quad\quad 98a=-26

\quad\quad a=-\dfrac{13}{49}

Now we can plug this value of a in any of the two equations.

49a-7b=-13

49\left(-\dfrac{13}{49}\right)-7b=-13

-13-7b=-13

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b=0

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

y=\left(-\dfrac{13}{49}\right)x^2+0x+0

y=-\dfrac{13}{49}x^2

49y=-13x^2

This our equation of the arch!

5 0
3 years ago
What is the area of a regular nonagon (9 sides) with side length of 15 cm and apothem of 20.6 cm? Round the answer to the neares
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We know that

<span>The nine radii of a regular Nonagon divides into 9 congruent isosceles triangles
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the answer is
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Licemer1 [7]

Answer:

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Step-by-step explanation:

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7 0
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