3 years ago

Your supposed to put the 4 answers in the correct spots. Please help!

Mathematics

1 answer:

andrew-mc [135]3 years ago

3 0

Answer:

I can't see the question

Step-by-step explanation:

sorry

maybe try asking the same question again

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Truth or Dare?<br> have a nice day

RoseWind [281]

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Step-by-step explanation:

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2 years ago

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The point slope of a line that has a slope of -2 and passes through point (5,-2) is shown below. Which equation is in slope inte

kramer

Y + 2 = -2(x - 5)

Simplify.

y + 2 = -2x + 10

Subtract 2 from both sides.

y = -2x + 10 - 2

Simplify.

y = -2x + 8 → Slope-intercept form

Our answer is the second option : y=-2x+8

~Hope I helped!~

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3 years ago

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The slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -2/3x + 6. What is the point-

Elena-2011 [213]

$y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so hmmm then we know the slope of that line is -2/3, so we're really looking for the point-slope form of a line with a slope of -2/3 and that passes through (-3 , 8)

$(\stackrel{x_1}{-3}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{(-3)})\implies y-8=-\cfrac{2}{3}(x+3)$