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Morgarella [4.7K]
2 years ago
15

I need help with this questions

Mathematics
1 answer:
kaheart [24]2 years ago
6 0

Answer:

1st question

63.63

2nd question

28.3

3rd question

25.1

4th question

70.4

5th question

1404.93

Step-by-step explanation:

1.

area= π×r^2

3.142×4.5squared

radius is 4.5

4.5 squared is 20.25

20.25×3.142 is 63.6255

2.d.p is 63.63

2.

circumference is pi times diameter

3.142×9 is 28.278

1.d.p is 28.3

3.

4×2=8 (diameter)

circumference is pi times diameter

3.142×8=25.136

1.d.p=25.1

4.

11.2×2=22.4(diameter)

circumference is pi times diameter

3.142×22.4=70.3808

1.d.p=70.4

5.

area is pi times radius squared

radius=11.2

11.2 squared is 125.44

3.142×125.44=1404.928

2.d.p=1404.93

hope this helps!

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Two circles with different radii have chords AB and CD, such that AB is congruent to CD. Are the arcs intersected by these chord
emmainna [20.7K]

The arcs intersected by these chords are not congruent.

Given that two circles with different radii have chords AB and CD, such that AB is congruent to CD.

Let r₁ and r₂ be the radii of two different circles with centers O and O' respectively.

Assuming that the each of the ∠АОВ  and ∠CO'D is less than or equal to π.

Then, we have isosceles triangle AOB and CO'D such that,

AO = OB = r₁,

CO' = O'D = r₂,

Let us assume that r₁< r₂;

We can see that arc(AB) intersected by AB is greater than arc(CD), intersected by the chord CD;

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Indeed,

arc(AB) = r₁ angle (AOB)

arc(CD) = r₂ angle (CO'D)

So, we have to prove that ;

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Since each angle is less than or equal to π, and so

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From triangle AOB :

tan(AOB/2) = AB/(2*r₁)

tan(CO'D/2) = CD/(2*r₂)

Since AB = CD and r₁ < r₂ (As obtained from the result of (3) ), therefore, arc(AB) > arc(CD).

Hence, for two circles with different radii have chords AB and CD, such that AB is congruent to CD but the arcs intersected by these chords are not congruent.

Learn more about congruent from here brainly.com/question/1675117

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