Question

Help!! Thank you so much!!

Answer 1

The volume we're looking for is the volume of both cones in the figure.

The volume of a cone is  $V=\pi r^2\frac{h}{3}$ .

So, $V_{tot} = V_{1} + V_2$ .

Cone 1's variables:

r = 2.6

h = 5

Cone 2's variables:

r = 2.6

h = 3

Now we can just plug and chug!

$V_{tot} = [(3.14)(2.6^2)(\frac{5}{3} )] + [(3.14)(2.6^2)\frac{3}{3} )]\\V_{tot} = [(3.14)(6.76)(1.67)] + [(3.14)(6.76)(1)]\\V_{tot} = (35.45) + (21.23)\\V_{tot} = 56.68$

V = c. 56.6 cubic units