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sveta [45]
3 years ago
5

How to change from standard for to vertex form

Mathematics
2 answers:
zalisa [80]3 years ago
8 0
If the equation is y = 3(x + 4)2<span> - 6, the value of h is -4, and k is -6. To convert a quadratic from y = ax</span>2<span> + bx + c </span>form to vertex form, y = a(x - h)2+ k, you use the process of completing the square. Let's see an example. Convert y = 2x2<span> - 4x + 5 into </span>vertex form<span>, and state the </span>vertex<span>.</span>
Arlecino [84]3 years ago
8 0
Standard form is
ax^2+bx+c=y
to change to vertex form
complete the square

HOW TO COMPLETE THE SQUARE
first, isolate the x terms
(ax^2+bx)+c=y
factor out a
a(x^2+(b/a)x)+c=y
take 1/2 of the coefient of the x term and square it
(b/a) time 1/2=b/(2a), square it, \frac{b^2}{4a^2}
now add positive and negative inside parenthasees
a(x^2+(b/a)x+\frac{b^2}{4a^2}-\frac{b^2}{4a^2})+c=y
factor perfect square
a(((x+ \frac{b^2}{4a^2})^2-a\frac{b^2}{4a^2})+c=y
distribute
a(x+ \frac{b^2}{4a^2})^2 -a \frac{b^2}{4a^2}+c=y
 a(x+ \frac{b^2}{4a^2})^2 - \frac{b^2}{4a}+c=y
that is vertex form and how to complete the square

for ax^2+bx+c=y
vertex form is
 a(x+ \frac{b^2}{4a^2})^2 - \frac{b^2}{4a}+c=y
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Read 2 more answers
Two drivers, Alison and Kevin, are participating in a drag race. Beginning from a standing start, they each proceed with a const
Vilka [71]

Answer:

Alison wins against Kevin by 0.93 s

Step-by-step explanation:

Alison covers the last 1/4 of the distance in 3 seconds, at a constant acceleration a_a, we have the following equation of motion

s/4 = a_at_a^2/2

where s (m) is the total distance, ta = 3 s is the time

s = 4a_a3^2/2 = 18a_a

a_a = s/18

Similarly, Kevin overs the last 1/3 of the distance in 4 seconds, at a constant acceleration a_k, we have the following equation of motion:

s/3 = a_kt_k^2/2

tk = 4 s is the time

s = 3a_k4^2/2 = 24a_k

a_k = s/24

Since a_a = s/18 we can conclude that a_a > a_k, so Alison would win.

The time it takes for Alison to cover the entire track

s = a_aT_a^2/2

T_a^2 = 2s/a_a = 2s/(s/18) = 36

T_a = \sqrt{36} = 6 s

The time it takes for Kevin to cover the entire track

s = a_kT_k^2/2

T_k^2 = 2s/a_k = 2s/(s/24) = 48

T_a = \sqrt{48} = 6.93 s

So Alison wins against Kevin by 6.93 - 6 = 0.93 s

4 0
3 years ago
HElp fasttttttttttttttttttttttttt
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9514 1404 393

Answer:

  -0.16

Step-by-step explanation:

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Here, that is a negative fraction of a unit. If we assume the value is a rational number that can be accurately determined from this graph, then we can find it by looking for a point where the graph crosses a grid intersection. It looks like such grid points are (-7, 0) and (3, 0). The vertex is apparently (-2, 4), so the vertex form of the equation is ...

  y = a(x +2)^2 +4

Using the point (3, 0), we have ...

  0 = a(3 +2)^2 +4 . . . . . fill in the values of x and y

  -4 = 25a . . . . . . . . . . subtract 4; next, divide by 25

  a = -4/25 = -0.16

7 0
3 years ago
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