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Svetllana [295]
2 years ago
13

Please help! Will mark brainlessest

Mathematics
1 answer:
suter [353]2 years ago
5 0
D.) D’(-3,-16)
Trans station is (x-5,y-16)
You might be interested in
What is the distance, to the nearest whole number, from K (5, 6) to P (1, 1)?
Elza [17]

Answer:

<h3>The answer is 6 units</h3>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

K (5, 6) P (1, 1)

The distance from K to P is

|KP|  =  \sqrt{ ({5 - 1})^{2} +  ({6 - 1})^{2}  }  \\  =  \sqrt{ {4}^{2} +  {5}^{2}  }  \\  =  \sqrt{16 + 25}  \\  =  \sqrt{41}  \\  = 6.403124

We have the final answer as

<h3>6 units to the nearest whole number</h3>

Hope this helps you

5 0
3 years ago
2 1/4+1/2(h+3/4) simplify
eimsori [14]

Answer: h/2 + 21/8

Step-by-step explanation:

7 0
2 years ago
30pts! im currently in the middle of taking the test :(
nadya68 [22]

Answer:

16 /65  +  28 i /65

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Someone help me find what is m
Yuri [45]

Answer:

measure of angle F=    109 degrees

Step-by-step explanation:

I believe by m you are solving for angle F.  So, angle H =71 degrees. GF and HI are parallel. In order to find angle G, Take the supplementary of 71 degrees, so 180-71 = angle G =109 degrees. Because GH and FI are congruent, the angles should be same across the shape, so angle I 71 degrees. Quadrilateral has a total of 360 degrees, so, 360-71-109-71=109 degrees. In general, angke G would equal angle F because of the trapezoid properties that take place when both bases are parallel and two of the sides are congruent, the trapezoid is an isosceles trapezoid

5 0
2 years ago
What two numbers can add to 4 but multiple to -12
olasank [31]

Answer:

<em>Numbers: 6 and -2</em>

Step-by-step explanation:

<u>Equations</u>

This question can be solved by inspection. It's just a matter of factoring 12 into two factors that sum 4. Both numbers must be of different signs and they are 6 and -2. Their sum is indeed 6-2=4 and their product is 6*(-2)=-12.

However, we'll solve it by the use of equations. Let's call x and y to the numbers. They must comply:

x+y=4\qquad\qquad [1]

x.y=-12\qquad\qquad [2]

Solving [1] for y:

y=4-x

Substituting in [2]

x(4-x)=-12

Operating:

4x-x^2=-12

Rearranging:

x^2-4x-12=0

Solving with the quadratic formula:

\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

With a=1, b=-4, c=-12:

\displaystyle x=\frac{-(-4)\pm \sqrt{(-4)^2-4(1)(-12)}}{2(1)}

\displaystyle x=\frac{4\pm \sqrt{16+48}}{2}

\displaystyle x=\frac{4\pm 8}{2}

The solutions are:

\displaystyle x=\frac{4+ 8}{2}=6

\displaystyle x=\frac{4- 8}{2}=-2

This confirms the preliminary results.

Numbers: 6 and -2

7 0
3 years ago
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