A train left a station at 8:13 a.m. arriving at its destination at 4:52 p.m. If the stations are 527.65 miles apart, calculate t

Question

lisov135 [29]

3 years ago

12

A train left a station at 8:13 a.m. arriving at its destination at 4:52 p.m. If the stations are 527.65 miles apart, calculate t

he average
speed at which the train traveled.
A. 71 miles/hour
B. 69 miles/hour
C. 51 miles/hour
D. 61 miles/hour

Mathematics

1 answer:

Tomtit [17] · Answer 1 · 2022-11-08T17:00:55+03:00

9514 1404 393

Answer:

D. 61 mi/h

Step-by-step explanation:

The travel time is 16:52 -8:13 = 8:39 hours, or 8.65 hours. Then the speed is ...

speed = distance/time = 527.65 mi/(8.65 h) = 61 mi/h

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<em>Additional comment</em>

It is often convenient to use "military" or "24-hour" time for calculations of time periods that extend over noon or midnight. For this purpose, 12 gets added to the hour number in the afternoon (pm). Of course, 39 minutes is 39/60 hours. That is found to be 0.65 hours by performing the division of 39 by 60.