Answer: Any real number x as long as 
and 
In other words, anything but 0 or -2/3 is valid.
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Explanation:
Set the denominator equal to zero and solve for x
2(3x^2 + 2x) = 0
3x^2 + 2x = 0
x(3x + 2) = 0
x = 0 or 3x+2 = 0 .... zero product property
x = 0 or 3x = -2
x = 0 or x = -2/3
If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.
Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.
Given equation is y=2x+7 and 
Let's simplify the 2nd equation before we can start graph so that calculation will be easy
multiply both sides by 2 to cancel out fractions
y=2x+7
which is exactly same as the first equatoin so graph of both will be exactly same and solution will be infinitely many solutions.
y=2x+7 has y-intercept 7 so first point will be (0,7). Slope is 2 so rise 2 unit up then 1 right and graph the new point.
Answer: 5, 6
Step-by-step explanation:
0 + 2 = 2
2 , 0
0 + 6 = 6
2, 6
2 + 3 = 5
5, 6
Answer: x³+2x²-15x
Step-by-step explanation:
1. Expand
(x²-3x)(x+5)
2. Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd
x³+5x²−3x²−15x
3. Collect like terms
x³+(5x²−3x²)−15x
4. Simplify
x³+2x²-15x
Hope this helps, have a BLESSED and wonderful day! ;-)
Answer:
22
Step-by-step explanation:
those are the answers for each but if it is asking which one has the highest number it would be the mean (average) because its 22 which is higher than the other answers
