Let the length of shortest side be - x
length of medium side - x +3
length of longest side - x +3 + 11
so , according to question
=> x + x +3 + x +3 + 11 = 59
=> x + x +x + 3 + 3 + 11 = 59
=> 3x = 59 - 17
=> 3 x = 42
=> x = 42/3
=> x = 14
Shortest side = x = 14
medium side = x + 3 = 14+3 = 17
longest side = x + 3 +11 = 14 + 3 + 11 = 28
Answer:
Option C.
Step-by-step explanation:
we know that
The probability of an event is the ratio of the size of the event space to the size of the sample space.
The size of the sample space is the total number of possible outcomes
The event space is the number of outcomes in the event you are interested in.
so
Let
x------> size of the event space (total person's hemoglobin level of 9 or above with age above 35 years)
y-----> size of the sample space (total person's age above 35 years)
so
In this problem we have
Complete the table to find the total person's hemoglobin level of 9 or above (person's age above 35)
Let
y------> total person's hemoglobin level between 9 and 11 (person's age above 35)


Find the value of x

substitute the values
Answer:
a=50
Step-by-step explanation:
a + 2a + 30 = 180
3a + 30 = 180
(-150 from both sides)
3a = 150
(Divide by 3 from both sides)
a = 50
Answer:

Step-by-step explanation:

<em>Option:</em>
<em>a. for every 13 dogs, there are 25 cats.
</em>
<em>b. there are twice as many cats as dogs at the shelter.
</em>
<em>c. the shelter has more dogs than cats.
</em>
<em>d. there are 25 animals in the shelter.</em>
Answer:
a. for every 13 dogs, there are 25 cats.
<em></em>
Step-by-step explanation:
Represent Dogs with D and Cats with C;
So;

By comparison:


This implies that:
For every 13 D, there are 25 C
Hence: Option A is true