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Jet001 [13]
2 years ago
7

5. Becca wants to edge her hexagonal garden

Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
6 0

Answer:

(a)\ Perimeter = 6l

(b)\ Cost = \$36l

Step-by-step explanation:

Given

l \to sides

Solving (a): The perimeter

The shape has 6 sides; since the sides are equal, the perimeter is:

Perimeter = 6 * l

Perimeter = 6l

Solving (b): Cost of fencing

We have:

Unit\ cost = \$6/yd

So, the cost is:

Cost = Unit\ cost * Perimeter

Cost = \$6/yd * 6l

Cost = \$36l

<em>To get the actual answer, substitute the length of one side of the hexagonal in the calculated expressions</em>

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Screenshot with answers included A circle has a radius of 1 cm.
lora16 [44]
Area = \pi  r^{2} 
area =  \pi x 1 x 1 = \pi 

Circumference = 2\pi r
Circumference = 2 x \pi x1
Circumference = 2\pi 

The circumference is greater than the area


6 0
3 years ago
Find the indicated real nth root(s) of a. n=3, a=729
marissa [1.9K]

Answer:

9

Step-by-step explanation:

n=3, a=729

For any odd integer, n ; a will have only one real nth root which will be a positive integer.

Similarly, for any integer, n, that is > 1 ; related by the expression ;

p^n = a ; the nth root of a = p

Therefore,

If n = 3 ; a = 729

p^3 = 729

To obtain the value of p ; take the cube of both sides

(p^3)*1/3 = 729^1/3

p = 9

Hence, the real nth root of 729 is +9 when n = 3

6 0
2 years ago
Help a brother out with this math shi
liraira [26]

(7^13)^3 * 7^0

= 7^(13 * 3) * 1

= 7^39

Answer

7^39

P.S. Any number (except 0) to the 0 exponent is equal to 1

6 0
3 years ago
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :
const2013 [10]

Answer:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.

This means that n = 1067, \pi = \frac{74}{1067} = 0.069

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

7 0
2 years ago
Find equation of a line passing through the points<br> (0, 2) and (6, 20)
Monica [59]

Step-by-step explanation:

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7 0
2 years ago
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