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3 years ago

Find the surface area of the triangular prism (above) using its net (below).

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

7 0

Answer:

It is 136

Step-by-step explanation:

r-ruslan [8.4K]3 years ago

3 0

Answer:

96 square units

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.

My answer:

The length of the large rectangle is: 5
The width of the large rectangle is: 7

=> Area of the large rectangle = length × width = 7*5 = 35 square units

The length of the middle rectangle is: 7
The width of the middle rectangle is: 4

=> Area of the middle rectangle = length × width = 7*4 = 28 square units

The length of the small rectangle is: 7
The width of the small rectangle is: 3

=> Area of the small rectangle = length × width = 7*3 = 21 square units

Area of top and the bottom triangles =2* $\frac{1}{2}bh$ $= 4*3 =12$

Total surface area = 35 + 28 + 21 + 12 = 96 square units

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Darina [25.2K]

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4 years ago

bill can paint a closet in 2 hours. bob can paint the same closet in 3 hours. how long will it take them to paint the closet tog

katen-ka-za [31]

Bill paints 1/2 per hour. Bob paints 1/3 per hour. 1/2x+1/3x=1

6 0

3 years ago

Fill in the blanks. Optionshouse tracked the performance of their most active day traders and found that the probability of a wi

Aleksandr [31]

Answer:

If in a day, 458 call options are picked by these traders, around <u> 246.2 </u>of them will be winners, give or take<u> 10.67 </u>.

Step-by-step explanation:

Hello!

Your study variable is X: the number of winning calls in a sample of 458 calls.

The variable has a binomial distribution since you have two possible outcomes, that the call is a winning call (success) or that the call is not a winning call (failure), each call is independent and the probability of success is p= 0.5375 and the probability of failure q= 1-p= 1-0.5375= 0.4625.

The expected value for a binomial distribution is

E(X)= n*p= 458 * 0.5375= 246.175

And to know the standard error (or standard deviation) you have to calculate the square root of the variance:

V(X)= n*p*q= 458*0.5375*0.4625= 113.85

√V(X)= √113.85= 10.67

I hope it helps!

3 0

3 years ago

Somebody please help with the ones I got wrong

iren2701 [21]

Answer:

7 = y= x+2 I think

8 = (-2, -1)

Step-by-step explanation:

5 0

3 years ago

Sophia's school took a field trip. a total of 21 vehicles were needed for the trip. some students took the bus, and some student

Liono4ka [1.6K]

Let x be the number of buses, and y the number of cars.
$\left \{ {{x+y=21} \atop {30x+4y=318}} \right.$
We can solve for y in the first equation to get:
$y=21-x$
Now we can replace 21-x in our second equation, and solve for x:
$30x+4(21-x)=318$
$30x+84-4x=318$
$26x=234$
$x= \frac{234}{26}$
$x=9$

We can conclude that 9 buses were needed for the trip.

4 0

4 years ago