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Marianna [84]
2 years ago
11

factor 3a^5-18a^3+6a^2, I know the answer is 3a^2(a^3-6a+2) but I am so lost on how to get the factor of 3a^2..How in the world

do you get the exponent for the factor
Mathematics
1 answer:
rusak2 [61]2 years ago
5 0

Answer:

\huge\boxed{3a^2(a^3-6a+2)}

Step-by-step explanation:

\sf 3a^5-18a^3+6a^2\\\\HCF = 3a^2\\\\Take \ 3a^2 \ common\\\\= 3a^2(a^3-6a+2)\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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Solve the inequlity 2s+5s+12=132<br> A. s=-30<br> B. s=40<br> C. s=120<br> D. s=9
Korvikt [17]
First off, an inequality means that there is no equals sign... it will be either greater than (>) or less than (<). So we'll solve yours with the assumption that it is supposed to be greater than...

2s + 5s + 12 > 132
7s + 12 > 132
7s > 132 - 12
7s > 120
s > 120/7
s > 17 1/7

**If it was supposed to be less than instead of greater than, just change the sign. It doesn't affect the outcome.
4 0
3 years ago
Please help with these algebra questions!!!! I will give brainliest
vitfil [10]

Answer:

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3 0
2 years ago
Mitchell bought 76 lb of cocoa powder for her Bakery every day she use the same amount of cocoa powder to make Bakery items afte
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3 years ago
Solve x2+4x+6=0 by graphing
klemol [59]

Answer: x = -2±√2 i or no real roots. See the explanation below.

Step-by-step explanation:

If you draw the graph, you will notice that there are no common points or you can say that there are no x-intercepts.

This means that the equation doesn't have any real roots.

If there are 2 common points (2 x-intercepts) then there are 2 real roots (answers.)

If there is only one common point (vertex is on x-axis) then there is only 1 real root.

If there aren't any common points (no x-intercepts) then there are no real roots.

So first, I'm gonna convert the equation into function and convert the standard form to vertex form.

x^2+4x+6=0\\y=x^2+4x+6\\y=(x^2+4x+4)-4+6\\y=(x+2)^2+2

We notice that the vertex is at (-2,2), the graph doesn't have x-intercepts (Graph below)

So the answer is clearly complex.

If you solve this by solving the equation then it'll be.

x^2+4x+6=0\\x= \frac{-b+-\sqrt{b^2-4ac}}{2a} \\x=\frac{-4+-\sqrt{16-24} }{2}\\x=\frac{-4+-\sqrt{-8} }{2}\\\\x=\frac{-4+-2\sqrt{2}i }{2}\\\\x={-2+-1\sqrt{2}i }\\\\

The answer is complex.

However, you can find the value of x easily by graphing. For example.

x^2+6x+5=0

Factor then you get

(x+5)(x+1)=0\\x=-5,-1

Or you can convert it to vertex form then graph.

y=x^2+6x+5

y=(x^2+6x+9)-9+5\\y=(x+3)^2-4

The vertex is at (-3,-4) then graph parabola (x-intercepts determine the roots of quadratic equation. For the graph, parabola intercepts x at (-5,0) and (-1,0) that means both -5 and -1 both are the value of x.

Note:

From the standard form, y=ax^2+bx+c The graph is called Parabola, and it's Quadratic Function.

a is how the graph is, for example. If a>0, the graph is supine parabola and if a<0 then the graph is inverted parabola.

|a| is determined if the graph is wide or narrow, the more the value of a is, the more narrow it will be. The less the value of a is, the more wide it will be.

b is what determined the change of graph (likely vertex). Without b, then it'd be ax^2+k which only move y-axis and not x-axis.

c is what determined the y-intercept and y-axis. If there is no b or the value of b is 0 then the vertex is at (0,c). If there is the value of b then c is only determined the y-intercept.

4 0
3 years ago
Kindly solve this question
Dmitry_Shevchenko [17]

Answer:

x=-1/7

Step-by-step explanation:

\frac{3x-1}{3} -\frac{2x}{x-1} =x

\frac{(3x-1)(x-1)}{3x-3} -\frac{2x(3)}{3x-3} =x

\frac{3x^2-4x+1}{3x-3} -\frac{6x}{3x-3} =x

\frac{3x^2-10x+1}{3x-3} =x

\frac{3x^2-10x+1}{3x-3} =\frac{x(3x-3)}{3x-3}

\frac{3x^2-10x+1}{3x-3} =\frac{3x^2-3x}{3x-3}

3x^2-10x+1=3x^2-3x

-10x+1=-3x

-7x=1

x=-1/7

3 0
2 years ago
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