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elena55 [62]
3 years ago
7

Tony's friends ate 0.6 of the appetizers he made. Which point on the number line best represents 0.6?

Mathematics
1 answer:
Nostrana [21]3 years ago
7 0
It’s letter c, cause
P=0,4
Q=0,6
R=0,8
S=1,0

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Write and solve a word problem involving money that can be solved with a multiplication equation
ololo11 [35]

Answer:

You have a stand that sells bags of oranges. 25lb sells for $5. You sell 3 bags. How much money did you make?

3 * 5 =$15

Step-by-step explanation:

You have a stand that sells bags of oranges. 25lb sells for $5. You sell 3 bags. How much money did you make?

3 * 5 =$15

6 0
4 years ago
Read 2 more answers
Solve for x:<br><br> x + 3 = 8
artcher [175]
How generous
x+3=8
minus 3 both sides
x+3-3=8-3
x+0=5
x=5
5 0
3 years ago
When two fractions with different denominators are to be added using the standard procedure, which of these must first be found?
FromTheMoon [43]

Answer:

3. The LCD (Least Common Denominator) of the fractions

Step-by-step explanation:

This is the first step to do in order to be able to properly add the fractions.

6 0
3 years ago
Twenty words were randomly selected from two textbooks. Each set gives the number of letters in each of the twenty words for tha
Alborosie

Answer:

k = 13The smallest zero or root is x = -10

Step-by-step explanation:

you can write "x^2" to mean "x squared"

f(x) = x^2+3x-10

f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5

f(x+5) = (x^2+10x+25)+3(x+5)-10

f(x+5) = x^2+10x+25+3x+15-10

f(x+5) = x^2+13x+30

Compare this with x^2+kx+30 and we see that k = 13

Factor and solve the equation below

x^2+13x+30 = 0

(x+10)(x+3) = 0

x+10 = 0 or x+3 = 0

x = -10 or x = -3

The smallest zero is x = -10 as its the left-most value on a number line.

7 0
3 years ago
What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
Anarel [89]

Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

Finding f(b) when b=1

f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1

Now, finding f(a), when a= -1

f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1

So, average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

4 0
3 years ago
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