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Ede4ka [16]
3 years ago
13

5/6 equals what over 30?

Mathematics
2 answers:
sergiy2304 [10]3 years ago
8 0
25 over 30 because 6x5=30 and 5x5=25
babymother [125]3 years ago
5 0
25/30 bc 6x6=30 and 5x5=25

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For the third week of February, Betty Robinson worked 46 hours. Betty earns $17.50 an hour. Her employer pays overtime for all h
anygoal [31]

Answer:

1. 700

2. $157.50

3. $857.50

Step-by-step explanation:

Regular pay is calculated by taking 40 hours x $17.50 to get $700.

Overtime is calculated by taking 6 hours x 17.50 x 1.50 to get $157.50

Gross pay would be adding these two amounts together.

6 0
3 years ago
!!!!!!!!! PLEASE HELP !!!!!!!!!!<br><br><br> Solve x² - 6x - 7 = 0
sesenic [268]

Answer:

x = 7, -1

Step-by-step explanation:

4 0
3 years ago
At the city museum, child admission is $5.20 and adult admission is $9.90 . On Monday, twice as many adult tickets as child tick
DiKsa [7]
To solve this, I would just find what two adult tickets and one child ticket wold be worth.

To find that, just do:

5.20 + 9.90 * 2, which makes 25.

So now you just find how many 25s are in 900, or 36.

So 36 children's tickets were sold that day.

Hope I helped :)
7 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
(07.05 MC)
WARRIOR [948]

Answer:

4y = 2

Step-by-step explanation:

9y + 5 = 7 + 3y + 2y

9y-2y-3y=7-5

4y=2

5 0
3 years ago
Read 2 more answers
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