ANSWER ASAP FOR BRAINLIEST THANKS

Mathematics

2 answers:

svet-max [94.6K]3 years ago

7 0

Nevermind i was wrong but it wont let me delete the answer

Luda [366]3 years ago

6 0

Answer:

A: 150

Step-by-step explanation:

I hope this helps! I might be wrong, so tell me if I am

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Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. B = 71°, a

mr_godi [17]

$\boxed{\text{Area of the triangle:} \dfrac{a \times c \times sin(\measuredangle B)}{2}} \\ \\ A = \dfrac{a \times c \times sin(\measuredangle B)}{2} \\ \\ A= \dfrac{11 \times 18 \times sin71 ^o }{2} \\ \\ \\ Note : sin 71^o \approx 0,94 \\ \\ \\ A = \dfrac{198 \times 0,94}{2} \\ \\ A= \dfrac{186.12}{2} \\ \\ A=93.6 \ cm^2$

6 0

2 years ago

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Grade 4

Lesechka [4]

The largest is 17.08
thank me later :)

6 0

2 years ago

The areas of two equilateral triangles are 27 yd2 and 75 yd2. Find the ratio of their perimeters.

Cloud [144]

If the areas of two equilateral triangles are 27 yd² and 75 yd², then the ratio of these areas is 27/75 = 9/25

If the ratios of the areas are 9:25, then their similarity ratio and the ratio of their perimeters is √9:√35 = 3:5.

3 : 5; 3 : 5 <==ANSWER

8 0

3 years ago

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Write nineteen and fifty eight thousandths as a decimal

MakcuM [25]

19.58 this is the answer

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2 years ago

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4vir4ik [10]

Answer:

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Step-by-step explanation:

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