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IgorLugansk [536]

3 years ago

14

(30 POINTS COME AND GET IT FOR A MULTIPLE CHOUCE XD) which of the following is the solution for s in the system of equation show

n below? R+2s=52
2r-s=4
(1)12
(2)15
(3)17
(4)20

2 answers:

Irina-Kira [14]3 years ago

6 0

Answer:

Sorry i just need points

Step-by-step explanation:

disa [49]3 years ago

3 0

Answer:

(4) s = 20

Step-by-step explanation:

<u>Given system:</u>

r + 2s = 52
2r - s = 4

Eliminate r to solve for s.

<u>To do so, double the first equation and then subtract the second one:</u>

2r + 4s = 104
2r - s = 4

<u>Subtract</u>

4s - (-s) = 104 - 4
5s = 100
s = 100/5
s = 20

Correct choice is (4) 20

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A=1/2bh solve for b then h

SIZIF [17.4K]

Answer:

There is no right or wrong answer

Step-by-step explanation:

You did not give enough information, this formula usually comes with a triangle that you want to solve, therefore no one can answer this correctly since there is nothing to solve.

5 0

3 years ago

Read 2 more answers

-3 \cdot f(-8) + 7 \cdot g(2) =−3⋅f(−8)+7⋅g(2)=minus, 3, dot, f, left parenthesis, minus, 8, right parenthesis, plus, 7, dot, g,

dsp73

Answer:

-22

Step-by-step explanation:

The graph from which the information is to be read is attached below.

We want to find the value of −3⋅f(−8)+7⋅g(2).

From the graph:

f(-8)=-2
g(2)=-4

Therefore:

−3⋅f(−8)+7⋅g(2)=−3(-2)+7(-4)

=6-28

=-22

−3⋅f(−8)+7⋅g(2)=-22

3 0

2 years ago

The equation of the line that contains the points (-8, 1) and (0, -5) is

posledela

Answer:

y = -3/4x -5 (G)

Step-by-step explanation:

Find the slope by using the slope formula. (It's hard to format here so look it up)

Basically, it is y2 - y1/x2 - x1

-5 - 1/ 0 + 8

-6/8 = -3/4

The slope is -3/4.

Plug in for y = mx + b

y (y coordinate) = -5

x (x coordinate) = 0

slope (m) = -3/4

-5 = -3/4(0) + b

-5 = 0 + b

b = -5

y = -3/4x -5

5 0

2 years ago

The formula A equals =P left parenthesis 1 plus r right parenthesis squared (1+r)2 gives the amount A in dollars that P dollars

vlabodo [156]

The interest rate is 3.5%.

EXPLANATION

We substitute the given values into the formula;

$A=P(1+\frac{r}{100})^t$

to obtain

$6427.35=6000(1+\frac{r}{100})^2$

We divide through by 6000 to obtain,

$\frac{6427.35}{6000}=(1+\frac{r}{100})^2$

This implies that,

$1.071225=(1+\frac{r}{100})^2$

We take the square root of both sides,

$\sqrt{1.071225}=(1+\frac{r}{100})$

This gives us,

$1.035=(1+\frac{r}{100})$

Add -1 to both sides of the equation to obtain

$0.035=\frac{r}{100}$

Multiply through by 100 to obtain;

$r=3.5$ %

$Therefore the rate is 3.5%$

3 0

3 years ago

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

2 years ago