Answer: a) yNA/100
b) NA(y-x)/100
c) (NA)/B
Step-by-step explanation:
a) The total amount of dollars owned by the shares' owner = N number of shares × A dollars per share = NA dollars
This total is then transferred to buy B shares which then appreciates by y%.
The amount of increase in portfolio from January to June = y% of total dollars invested = y% of NA dollars = yNA/100
b) If the shares were left with A, the increase in portfolio from January to June would be x% and = x% of the total Dollar amount = x% of NA dollars = xNA/100
How much more money made in that time would be the difference in interest, between taking the dollars to invest in share B or keeping the dollars on investment A
That is, (yNA/100) - (xNA/100) = NA(y-x)/100
c) Total dollars available after sale of the A stock = NA
Number of B stock this dollar can buy = Total dollars available/amount of B stock per share
That is, (NA)/B
QED!
I think your question isn’t phrased well
Answer:
B
Step-by-step explanation:
The first step is to draw the line y = 3 - x to see what the line itself looks like. Is it going from left to right as in A and C is going up as you go from right to left as in B and D? The graph on the left (below) gives you the answer. It is going up as you progress from right to left.
The next step is to answer which is it: B or D.
y has to be above the line. it is B. See the graph below on the right.
The answer to the missing value is X = 3