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3 years ago

Acetylene, C2H2 (also known as ethyne), is commonly used as a fuel for welding torches.

Chemistry

1 answer:

Lisa [10]3 years ago

8 0

Answer:

True

Explanation:

Acetylene or Ethyne is the simples form of hydrocarbon with triple bond in it. It is the first member of alkyne series. It colorless, highly inflammable gas. This is why is used in oxy-acetylene torches used for welding and cutting materials. It is also used as raw material in synthesis of many organic chemicals and plastics.

So, the given statement is true.

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Iron (III) oxide and hydrogen react to form iron and water, like this: Fe 03(s)+3H9)2Fe(s)+3HO) At a certain temperature, a chem

belka [17]

The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound Amount

Fe₂O₃ 3.95 g

H₂ 4.77 g

Fe 4.38 g

H₂O 2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

Answer: The value of equilibrium constant for given equation is $1.0\times 10^{-4}$

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

For hydrogen gas:

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M$

For water:

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M$

For the given chemical equation:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression of equilibrium constant for above equation follows:

$K_{eq}=\frac{[H_2O]^3}{[H_2]^3}$

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}$

Hence, the value of equilibrium constant for given equation is $1.0\times 10^{-4}$

6 0

4 years ago

What is the effect of photosynthesis in the carbon dioxide cycle

iren [92.7K]

Answer: joe mama

Explanation: joe mama

8 0

3 years ago

Read 2 more answers

How many moles are in 25 g of NaCl

Olenka [21]

4.5098 moles i believe'

3 0

3 years ago

"Why is Co2, so bad for our bodies and why do we need to remove it?”

zavuch27 [327]

Because it is an asphyxiant.

4 0

3 years ago

Given the following chemical reaction: 2 O2 + CH4 CO2 + 2 H2O What mass of CH4 is required to completely react with 100 grams of

AfilCa [17]

Answer:

The mass methane (CH4) required is, 25 grams (option C)

Explanation:

Mass of oxygen gas = 100 g

Molar mass of oxygen gas = 32 g/mole

Molar mass of methane gas = 16 g/mole

Step 1: Balance the reaction

2O2 + CH4 → CO2 + 2H2O

Step 2: Calculate the moles of O2:

Moles O2 = mass of O2 / Molar mass of o2

Moles O2 = 100g / (32g/mole) = 3,125 moles

⇒From the balanced reaction we conclude that 2 moles of O2 react with 1 mole of CH4

⇒ So, 3.125 moles of O2 react with 3.125/2 = 1.563 moles of CH4

Step 3: Calculate the mass of CH4:

Mass of CH4 = moles of CH4 x Molar mass of CH4

Mass of CH4 = 1.563 moles / (16g/ moles) = 25.008 grams CH4

6 0

4 years ago