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AlladinOne [14]
3 years ago
14

An boron isotope consist of 5 protons 5 electrons and 6 neutrons its mass number is ?

Chemistry
1 answer:
vichka [17]3 years ago
8 0
10.811 atomic mass units
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Convert -32 F into K
Afina-wow [57]

Answer:

-32 Fahrenheit converts to 237.594 Kelvin

4 0
3 years ago
They are substances that produce ions when they dissolve in water.
stira [4]

Electrolytes are substances that produce ions when they dissolve in water.

What are electrolytes?

When some substances are dissolved in water, they undergo physical or chemical changes, creating ions in solution. These substances form an important class of compounds called electrolytes. Substances that do not release ions when dissolved are called non-electrolytes. A substance is said to be a strong electrolyte if the physical or chemical process that produces ions is inherently 100% efficient (all dissolved compounds produce ions). A solute is said to be a weak electrolyte if only a relatively small portion of the solute undergoes ion production processes.

By measuring the electrical conductivity of aqueous solutions containing substances, substances can be identified as strong, weak, or non-electrolyte. To conduct electricity, a substance must contain free-moving charged species. The best known is the conduction of electricity through metal wires. In this case, the mobile charged unit is the electron.

Therefore, Electrolytes are substances that produce ions when they dissolve in water.

To know more about electrolyte, visit:

brainly.com/question/17089766

#SPJ4

7 0
1 year ago
Calculate the volume of 0.684mol of carbon dioxide at s.t.p. show working
solong [7]

Answer: The volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles = 0.684

R = gas constant = 0.0821Latm/Kmol

T =temperature =273K   (at STP)

V=\frac{nRT}{P}

V=\frac{0.684\times 0.0821L atm/K mol\times 273K}{1atm}

V=15.3L

Thus the volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

6 0
3 years ago
if 5430 J of energy is used to heat 1.25 L of room temp. water (23.0 °C) whats the final temp of the water?
skelet666 [1.2K]

<span>We can use the heat equation,
Q = mcΔT </span>

 

<span>Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is the temperature difference (°C).</span>


Density = mass / volume


The density of water = 0.997 g/mL

<span>Hence mass of 1.25 L (1250 mL) of water = 0.997 g/mL x 1250 mL</span>

<span>                                                                   = 1246.25 g</span>


Specific heat capacity of water = 4.186 J<span>/ g °C.</span>


Let's assume that there is no heat loss to the surrounding and the final temperature is T.

By applying the equation,

      5430 J = 1246.25 g x 4.186 J/ g °C x (T - 23) °C
(T - 23) °C = 5430 J / 1246.25 g x 4.186 J/ g °C
(T - 23) °C = 1.04 °C
               T = 1.04 °C + 23 °C
               T = 24.04 °C

Hence, the final temperature of the water is 24.04 °C.
4 0
3 years ago
Given the equation: 2H2 + O2 → 2H2O, how many moles of oxygen are needed to react with 13 moles of hydrogen
bulgar [2K]

Explanation:

2H2 + O2 = 2H2O

2mol. 1mol. 2mol

2mol reacts with 1mol

13mol reacts with x

x=<u>13mol</u><u> </u><u>×</u><u> </u><u>1mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>2mol</u>

x= <u>13mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2mol

x= 6.5mol of oxygen

6 0
2 years ago
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