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2 years ago

P l e a s e help me omg I'm so confused-I'll give 40 points, I only have 45-

Chemistry

1 answer:

stiks02 [169]2 years ago

7 0

M is not as thick as N, It only takes 100°C to boil water whereas it takes 300°C to boil soybean oil

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Balance the equation in the box. Click in the answer box to activate the palette. N2(g) + H2(g) → NH3(g)

lesantik [10]

Answer:

N2(g) + 3H2(g) → 2 NH3(g)

Explanation:

N2(g) + H2(g) → NH3(g)

We start equaling the number of N atoms in both sides multiplying by 2 the NH3.

N2(g) + H2(g) → 2 NH3(g)

So we equals the H atoms (there are six in products sites)

N2(g) + 3 H2(g) → 2 NH3(g)

7 0

2 years ago

Compare the three atom diagrams. which one shows the electron with the highest potential energy

lara31 [8.8K]

Answer : The one diagram which shows the electron with the highest potential energy is attached below.

Explanation : One can easily find the highest potential energy of the atom just by looking at the diagram, the electron which is from farthest distance from the atomic nucleus will have the highest potential energy in the electron.

5 0

2 years ago

What is the difference between a material having the chemical property of being flammable vs having the chemical property of bei

makkiz [27]

Answer:

Being flammable means it supports burning,e.g. Oxygen, but being combustible means burning itself too. e.g. Hydrogen.

Explanation:

Hope it helps!!

4 0

2 years ago

100 Points Will Make Brainliest. Help Me Please.

Oksana_A [137]

If the glasses and glove were wrong then I would chose the fire extinguisher and the power source should be the correct answer.

That's just what I would do though.

3 0

3 years ago

Read 2 more answers

The vapor pressure of water at 65oC is 187.54 mmHg. What is the vapor pressure of a ethylene glycol (CH2(OH)CH2(OH)) solution ma

Pavlova-9 [17]

Answer:

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

Explanation:

Vapor pressure of water at 65 °C= $p_o= 187.54 mmHg$

Vapor pressure of the solution at 65 °C= $p_s$

The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.

Mass of ethylene glycol = 22.37 g

Mass of water in a solution = 82.21 g

Moles of water= $n_1=\frac{82.21 g}{18 g/mol}=4.5672 mol$

Moles of ethylene glycol= $n_2=\frac{22.37 g}{62.07 g/mol}=0.3603 mol$

$\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}$

$\frac{187.54 mmHg-p_s}{187.54 mmHg}=\frac{0.3603 mol}{0.3603 mol+4.5672 mol}$

$p_s=173.83 mmHg$

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

6 0

2 years ago