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MissTica
3 years ago
14

Part B. How much would it cost to buy a cover for the pool that costs $0.30 per square foot? Enter your answer in the box. Image

above​

Mathematics
1 answer:
spayn [35]3 years ago
8 0
I think it’s 12,000 if that’s an answer
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Please help me with this question
romanna [79]

Answer:

E.

Step-by-step explanation:

so first you would add 8 to both sides to get

3w = t + 8

then divide both sides by 3

w = (t + 8) / 3

So the answer is E.

3 0
3 years ago
Read 2 more answers
A survey asked only girls to identify their favorite item on the
MA_775_DIABLO [31]

Answer:

B

Step-by-step explanation:

A biased sample is a sample that does not accurately represent the population.

The survey asked only girls, but we can assume this school has both boys and girls. Therefore, by only asking girls, it creates a bias, because the boys in the school are not represented.

Therefore, the correct choice is B: biased sample.

6 0
3 years ago
Explain how this diagram can represent 3 - 7 = n​
k0ka [10]
The answer is 4 so n = 4
7 0
3 years ago
Read 2 more answers
Plant A: A graph has time (weeks) on the x-axis, and height (inches) on the y-axis. A line goes through points (0, 3), (1, 4.8),
butalik [34]

Answer:

The correct option is;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks

Step-by-step explanation:

The parameters given are;

Plant A:

Weeks,    Height

0,               3

1,                4.8

2,               6.6

3,               8.4

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant A per week is therefore;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{8.4 - 3 }{3 - 0} = \dfrac{5.4}{3} = 1.8 \ inches/week

Therefore we have;

H = 1.8 × t + 3

At week 6,

H = 3 + 6×1.8 = 13.8 inches

Plant B

Weeks,    Height

2,               7.3

3,               8.7

4,               10.1

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant B per week is given as follows;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{10.1 - 7.3 }{4 - 2} = \dfrac{2.8}{2} = 1.4 \ inches/week

Therefore we have;

When t = 2, H = 7.3 hence, 7.3 = 2 × 1.4 + H₀

Where:

H₀ = H at t = 0

H₀ = 7.3 - 2 × 1.4 = 4.5

At week 6 we have;

H = 4.5 + 6×1.4 = 12.9 inches

Which indicates that Plant A will be 0.9 inches taller than Plant B at week 6.

The correct option is therefore;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks.

5 0
3 years ago
Read 2 more answers
The sample size needed to estimate the difference between two population proportions to within a margin of error E with a signif
devlian [24]

Answer:

n= (z)22E2

n=10× 99%÷ 0.07

3 0
3 years ago
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