Snack in our class occurs at 9:50 am. We eat lunch at 12:05 pm. How long to students need to wait

Mathematics

2 answers:

Novay_Z [31]3 years ago

7 0

Answer:

2 hours and 15 minutes

Step-by-step explanation:

Arte-miy333 [17]3 years ago

4 0

Answer:

Students will need to wait 2 hours and 15 minutes

Step-by-step explanation:

Using 9:50 AM we can add 10 minutes so it can become 10:00 AM then we can add 2 hours making it 12:00 PM then add 5 minutes to make it 12:05 PM for the time of lunch. Giving us 2 hours and 15 minutes.

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Answer:

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Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

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Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

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