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2 years ago

Can u guys PLEASE ANSWER THIS QUESTION ASAP URGENTLY

Mathematics

1 answer:

makvit [3.9K]2 years ago

3 0

Answer:

x^2-4x+3

Step-by-step explanation:

Since the zeroes of the quadratic are 1 and 3, we can set up an equation in factored form:

(x-1)(x-3)

=x^2-4x+3

We can further check that this is the right answer by evaluating it at the vertex:

(2)^2-4*2+3=-1

Since that corresponds to the graph, the answer is x^2-4x+3

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What is <br> 5(2x+8)-5x=5(5x+6?

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Distribute

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3 years ago

Find the terminal point on the unit circle determined by pi radians.

svet-max [94.6K]

Answer:

Terminal points

$(x,y) = (\frac{1}{\sqrt{2} }) , (\frac{-1}{\sqrt{2} })$

Step-by-step explanation:

According to the question, it is provided that

$\theta = \frac{7\pi}{4}$

Now

$x = 1. cos (\frac{7\pi}{4})\\\\ = cos (2\pi - \frac{\pi}{4})\\\\= cos \frac{\pi}{4} \\\\= \frac{1}{\sqrt{2} }$

$y = 1. sin (\frac{7\pi}{4})\\\\ = sin (2\pi - \frac{\pi}{4})\\\\= -sin \frac{\pi}{4} \\\\= \frac{-1}{\sqrt{2} }$

Now

$(x,y) = (\frac{1}{\sqrt{2} }) , (\frac{-1}{\sqrt{2} })$

These two represents the terminal points

We simply applied the above equations and then equate these two equations to determine the terminal points and therefore the same is to be considered

It could be figure out by using the x and y points

Therefore the two shows the terminal points

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3 years ago