Answer:
I would like to answer but where is the picture for the question. Download that to this page and i will answer it. Have a great day
Step-by-step explanation:
Answer:
The p value for this case would be given by:
Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.
Step-by-step explanation:
Information provided
represent the sample mean
represent the population deviation
sample size
represent the value that we want to test
represent the significance level
z would represent the statistic
represent the p value
Hypothesis to test
We want to test if the true mean is at least 20 ounces, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic is given by:
(1)
Replacing the info given we got:
The p value for this case would be given by:
Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.
We can look at this graph y=cosx+5 as a translated graph. This is the same as the standard graph y=cosx being shifted 5 units upward.
The function y=cosx has the minimum y value of -1, meaning the smallest number the graph can have on the y axis is -1. Adding 5 to -1, we have 4.
Therefore, the minimum y value of y=cosx+5 is y=4.
Answer:
60 adults and 90 students.
Step-by-step explanation:
90x4= 360
60x6= 360
360+360=720
We are given the
perimeter of isosceles trapezoid = 28 in
ratio of length of bases = 5:3
We are to find the lengths of sides of the trapezoid and the diagonal that bisects the angle at the base with a longer length
The formula for the perimeter of an isosceles trapezoid is
P = (1/2) (b1 + b2) h
We are given the ratio
b2/ b1 = 5 /3
b2 = 5/3 b1
Substituting
28 = (1/2) (5/3 b1) h
The height of the trapezoid is expressed in terms of b1
For the diagonal
d² = h² + [(b2 - b1) + (b2 - b1)/2]²
Express h and b2 in terms of b1 and diagonal can be expressed in terms of b1
